Existence of minority carriers

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In summary, minority carriers exist in a p-type material due to the presence of electrons in the valence band while majority charge carriers (holes) are present. However, in this equilibrium situation, the concentration of minority carriers is continuously being reduced by recombination with excess holes. Even in doped semiconductors, where the electron concentration is increased, the concentration of minority carriers is still significantly lower due to the balance between thermal generation and recombination.
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Aranion
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why do minority carriers exist? in a p-type material, why don't the minority carriers recombine (and get annihlated) with excess holes?
 
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in P type if there are any minority carriers (electrons) in Valence band where majority charge carriers (holes) are present then they will recombine but minority carriers in p type which are electrons will be in conduction band while holes will be in valence band
 
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  • #3
Aranion said:
why don't the minority carriers recombine with excess holes?

They do. But you have to understand that this is an equilibrium situation where electron-hole pairs are also continuously being thermally generated. So yes, the concentration of minority carries DOES indeed get seriously reduced in a doped semiconductor, but not reduced to zero.

For example the "intrinsic" carrier concentration in Si is about [itex]10^{10}[/itex] [itex]cm^{-3}[/itex] at about 27C. This means that electrons and holes are being thermally generated (continuously) and also recombining (continuously) such that the steady state concentration of each is approx [itex]10^{10}[/itex] [itex]cm^{-3}[/itex]. The product of electron times hole concentration will be approx [itex]n p = 10^{20}[/itex].

Now if we dope the Si with say [itex]10^{16}[/itex] [itex]cm^{-3}[/itex] donor ions then the electron concentration will increase to approx [itex]10^{16}[/itex]. As a result the amount of recombination will increase whereas the amount of thermal generation will remain largely unchanged and the product will still be [itex]n p = 10^{20}[/itex]. So this means we'll now have [itex]p = 10^4[/itex] [itex]cm^{-3}[/itex], which is one million times lower concentration of holes (minority carriers) than in the undoped silicon.
 
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  • #4
thank you guys... i get it now..
 

1. What are minority carriers in a semiconductor material?

Minority carriers are electric charge carriers that exist in a semiconductor material in smaller quantities compared to the majority carriers (electrons or holes). They are generated by impurities or defects in the material and have a shorter lifetime compared to majority carriers.

2. How do minority carriers affect the conductivity of a semiconductor?

Minority carriers contribute to the conductivity of a semiconductor by increasing the number of charge carriers available for conduction. However, their shorter lifetime also results in a lower overall conductivity compared to majority carriers.

3. What is the importance of minority carriers in semiconductor devices?

Minority carriers play a crucial role in the functioning of semiconductor devices such as diodes, transistors, and solar cells. Their presence allows for the control and manipulation of current flow in these devices, making them essential for electronic technology.

4. How do minority carriers affect the performance of a solar cell?

In a solar cell, minority carriers (generated by the absorption of light) contribute to the photocurrent, which is the current generated by the device. However, their recombination with majority carriers also reduces the efficiency of the solar cell.

5. How is the concentration of minority carriers controlled in a semiconductor material?

The concentration of minority carriers can be controlled by introducing impurities or defects in the material through a process called doping. Doping with donors (such as phosphorus) increases the concentration of minority carriers, while doping with acceptors (such as boron) decreases their concentration.

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