miniake said:Homework Statement
Find the vector equation of line in three dimensional space that contains the point
P = (-1,3,0) and is orthogonal to the plane 3x - z = 2.
Homework Equations
The attempt at a solution
can I use the equation of (P-P0)n = 0 , in this question?
Since the only problem is, I don't know how to find the intersection point between the vector and the plane.
Any hints? Thanks.
A normal vector is a vector that is perpendicular, or at a 90 degree angle, to a given plane or surface. It can also be thought of as the direction in which a surface is facing.
To find the normal vector of a plane, you can use the cross product of two vectors that lie in the plane. The resulting vector will be perpendicular to both of those vectors and therefore, the normal vector of the plane.
Yes, you can find the normal vector with just one point on the plane and the equation of the plane. The normal vector will be the coefficients of the x, y, and z variables in the equation of the plane.
The normal vector and the slope of the plane are related by the following equation: slope = - (A/B), where A and B are the coefficients of the x and y variables in the equation of the plane. This means that the slope of the plane is the negative reciprocal of the normal vector's x-y slope.
Yes, the normal vector can be used to calculate the angle between two planes. This can be done by finding the dot product of the two normal vectors, and then using the inverse cosine function to find the angle between them.