Understanding displacements of points by interpreting directions

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In summary, given points x and y in Euclidean space, point x is displaced to point x1 by the formula x1=x+a(x-y), where a is a positive number. This results in a larger distance between x1 and y compared to the distance between x and y. This update rule can be interpreted as a force or direction from point y to point x. In the case of negative a, the update is x1=x+a(y-x), indicating a force or direction from point x to point y. This can be visualized as adding the vector a(x-y) to the vector ##\vec{OX}##, resulting in the new vector ##\vec{OX_1}##.
  • #1
onako
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Suppose that points x and y are given in Euclidean space. Point x is displaced to point x1 by

x1=x+a(x-y)

Given that a is positive number, how can it be shown that the distance x1 to y is larger than distance x to y. I'm mainly interested in a vector interpretation of the above update rule. In that sense, can (x-y) in the above rule be interpreted as
direction (force) from point y to point x? Similar interpretation is welcome.

Given negative a, the update is x1=x+a(y-x), so now the above intuition of a force is direction from point x to point y.
 
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  • #2
hi onako! :smile:
onako said:
… can (x-y) in the above rule be interpreted as
direction (force) from point y to point x?

yes, that's exactly correct :smile:

x-y is the vector ##\vec{YX}##, with magnitude |YX| and direction from Y to X
 
  • #3
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.
 
  • #4
onako said:
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.

ah, no, it isn't added to a point, it's added to the vector ##\vec{OX}## …

##\vec{OX} + a\vec{XY} = \vec{OX_1}## :smile:

draw the triangle, and you'll see why! :wink:
 
  • #5


I can provide a response to your question by explaining the vector interpretation of the given update rule.

First, let's define the vector a as a displacement vector that represents the distance and direction from point x to point y. This can be represented as a vector pointing from x to y, with a magnitude equal to the distance between the two points.

Now, in the update rule x1=x+a(x-y), the term (x-y) can be interpreted as a vector pointing from point y to point x. This vector represents the direction and magnitude of the displacement from point y to point x. This can be thought of as a force acting on point x, pulling it towards point y.

Since a is a positive number, it can be seen as a multiplier of the displacement vector (x-y). This means that the displacement of point x, x1, will be larger than the original distance between x and y, as it is being pulled by a greater force towards point y.

Similarly, in the case of negative a, the update rule x1=x+a(y-x) can be interpreted as a force acting on point x, pushing it towards point y. In this case, the displacement of point x, x1, will be smaller than the original distance between x and y, as it is being pushed away from point y.

In summary, the update rule can be interpreted as a force acting on point x, either pulling it towards or pushing it away from point y, resulting in a displacement to a new point x1. The magnitude of this displacement is dependent on the magnitude of the force, represented by the value of a.
 

1. What is the concept of displacement and why is it important in science?

Displacement is the change in position of an object or point in space. It is an important concept in science because it helps us understand the motion and movement of objects in relation to their surroundings. By studying displacements, scientists can make predictions about the future position of an object and analyze its motion over time.

2. How do you interpret directions when analyzing displacements?

Directions can be interpreted using a coordinate system, such as a Cartesian coordinate plane. The direction of an object's displacement can be described using either the cardinal directions (north, south, east, west) or angles (in degrees or radians) relative to a fixed reference point. The direction can also be represented by a vector, which includes both magnitude (distance) and direction.

3. How are displacements different from distance traveled?

Displacement is a vector quantity that describes the overall change in position of an object, while distance traveled is a scalar quantity that describes the total length of the path traveled by an object. Displacement takes into account both the magnitude and direction of the movement, whereas distance traveled only considers the total distance covered regardless of direction.

4. What are some real-life examples of displacements of points?

Examples of displacements of points can be found in various scenarios, such as a car traveling from one location to another, a person walking around a park, or a ball being thrown from one point to another. In each of these examples, the displacement would be the change in position from the starting point to the ending point.

5. How do you calculate the displacement of a point?

To calculate the displacement of a point, you need to know the initial position and the final position of the point. The displacement can be calculated by subtracting the initial position from the final position. This will give you a vector that represents the direction and magnitude of the displacement. Alternatively, you can use the Pythagorean theorem to calculate the displacement if you have the distance and angle of the movement.

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