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kakxy
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Homework Statement
A compound only contains C, H and O. An elemental analysis of the compound gives the result C: 40.00%; H: 6.71%. The 13C NMR, IR spectrum and mass spectrums are in the graph below.
Graphs: http://s512.photobucket.com/albums/t323/antiuniverse/graphs.gif
I need to determine the name of the compound.
Homework Equations
N/a
The Attempt at a Solution
I'm not entirely sure. From the elemental analysis:
If we had 100g of compound, we'd have:
40g C
6.71g H
53.29 O
Work out the moles:
40g / 12 = 3.3333 moles of C
6.71g / 1 = 6.7100 moles of H
53.29g / 16 = 3.3306 moles of O
Divide by smallest ratio:
2.8571 / 2.8571 = 1 atom of C
6.7100 / 2.8571 = 2 atoms of H
1.1652 / 2.8571 = 1 atom of O
So the empirical formula would be H2CO (or C2H4O2?). I think the mass spectrum is telling me that the empirical formula must be H2CO (which has a molecular weight/mass of 30).
From the 13C NMR spectra I believe it's either an aldehyde or ketone. I know that H2CO is formaldehyde (methanal) which is an aldehyde and correlates with what I found in the 13C NMR spectra.
Could anybody look over this and let me know if it's correct?
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