- #1
Lyuokdea
- 154
- 0
So we were going through Faraday's Law today in class:
[tex]\int\vec{E}\cdot d\vec{l} = -\frac{d}{dt}\int\vec{B}\cdot d\vec{A}[/tex]
Mathematically I'm fine with it, however, is there any good physical way to explain it, it seems very odd that if you had a field such as:
[tex]\vec{B} = B_0cos(\omega t)\hat{z}[/tex]
and that field was defined only in some circle of radius R that if you had a ring around R that the induced electrical current would be the greatest when the magnetic field doesn't exist, how does one object feel another objects change through time? I understand this in terms of a force for things like velocity, but that is only because the objects are in physical contact, however, the magnetic field isn't touching the right at all.
I would assume that there are photons moving between the field and the wire, or virtual photons or something would be necessary for the wire to "see" the magnetic field at all, however when those photons don't exist, how does the magnet react to them?
~Lyuokdea
[tex]\int\vec{E}\cdot d\vec{l} = -\frac{d}{dt}\int\vec{B}\cdot d\vec{A}[/tex]
Mathematically I'm fine with it, however, is there any good physical way to explain it, it seems very odd that if you had a field such as:
[tex]\vec{B} = B_0cos(\omega t)\hat{z}[/tex]
and that field was defined only in some circle of radius R that if you had a ring around R that the induced electrical current would be the greatest when the magnetic field doesn't exist, how does one object feel another objects change through time? I understand this in terms of a force for things like velocity, but that is only because the objects are in physical contact, however, the magnetic field isn't touching the right at all.
I would assume that there are photons moving between the field and the wire, or virtual photons or something would be necessary for the wire to "see" the magnetic field at all, however when those photons don't exist, how does the magnet react to them?
~Lyuokdea