Master Coulomb's Law with Expert Help: Quiz Prep for Electric Force Problems!

[Femme06Fatale]

I was wondering if anyone would be willing to walk me through a few problems to help prepare me for a quiz tomorrow over Coulomb's law. It'd be of great appreciation if anyone would/could help me!


The first problem:
Betelgeuse, one of the brightest stars in the constellation of Orion, has a diameter of 7.0 x 10 ^11 m. Consider two compact clouds w/ opposite charge equal to 1.0 x 10 ^5 C. If these clouds are located 7.0 x 10^11m apart, what is the magnitude of the electric force of attraction between them?

 

[jlorino]

Try using the formual
$$F=K\frac{q_{1}q_{2}}{d^2}$$
$$K=8.93\cdot10^9 \frac{Nm^2}{C^2}$$

 

[thepatientmental]

Sure, I'd be happy to help you with some Coulomb's law problems! Let's start with the first problem you mentioned about Betelgeuse and the two charged clouds.

To solve this problem, we can use the formula for Coulomb's law, which states that the magnitude of the electric force between two charged objects is equal to the product of their charges divided by the square of the distance between them, multiplied by the constant k, which is equal to 9 x 10^9 N*m^2/C^2.

So, in this problem, we have two clouds with opposite charges of 1.0 x 10^5 C. Plugging this into the formula, we get:

F = (1.0 x 10^5 C * 1.0 x 10^5 C) / (7.0 x 10^11 m)^2 * 9 x 10^9 N*m^2/C^2

Simplifying this, we get:

F = (1.0 x 10^10 C^2) / (49 x 10^22 m^2) * 9 x 10^9 N*m^2/C^2

Now, we can cancel out the units of C^2 and m^2, and we are left with the unit of force, N. So, our final answer is:

F = 1.8 x 10^-3 N

This means that the magnitude of the electric force of attraction between the two charged clouds is 1.8 x 10^-3 Newtons.

I hope this helps you understand how to solve this type of problem using Coulomb's law. Let me know if you have any other questions or if you need help with any other problems. Good luck on your quiz tomorrow!