- #1
rafaelpol
- 17
- 0
Homework Statement
Can't get to the final equality ( integral = - 4*Pi/3).
Homework Equations
[tex]
\int_V \mathbf{E }dV = - \int_F \frac{_{\mathbf{p}.\mathbf{e_{r}}}}{r^2}\mathbf{e_{r}}r^{2}d\Omega = \mathbf{p}\frac{-4\pi }{3}
[/tex]
The Attempt at a Solution
Can't find how to get -4Pi/3. In the way I am doing the r^2 would cancel out, the unit radial vectors would multiply each other to give one, and since p is the dipole moment vector and is constant in the problem (two point charges), it would get out of the integral. The integral over the solid angle d(omega) would then be equal to 4*Pi, and the answer would p*4Pi. Something is wrong here and I don't know what. Can anyone help?
Thanks