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Laplace Equation Solved by Method of Separation of Variables |
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| Nov12-12, 08:36 PM | #1 |
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Laplace Equation Solved by Method of Separation of Variables
1. The problem statement, all variables and given/known data
![]() 2. Relevant equations Assume the solution has a form of: ![]() 3. The attempt at a solution ![]() ![]() ![]() ![]() It looks like a sine Fourier series except for the 2c5 term outside of the series, so I'm not sure how to go about solving for the coefficients c5 and c10. Any idea? |
| Nov13-12, 06:56 AM | #2 |
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When lambda is zero, X(x) is identically zero, which means X(x)Y(y) is also zero. So there must be nothing in front of the series.
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| Nov13-12, 08:45 PM | #3 |
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| Nov13-12, 09:24 PM | #4 |
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Laplace Equation Solved by Method of Separation of Variables
I am puzzled by the boundary condition$$
\left. \frac{\partial u}{\partial y}\right |_{y=0} = u(x,0)$$Is that supposed to be the same ##u## on both sides? Or is it just another way to say something like$$ u_y(x,0) = f(x)$$some arbitrary function ##f##? |
| Nov14-12, 11:49 PM | #5 |
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| Nov15-12, 11:17 AM | #6 |
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OK. With that clarification for me, I would just comment about the last three lines. You already know you should have no eigenfunction for ##\lambda = 0##. Your eigenvalues are ##\lambda_n = n\pi##. Your third line from the bottom should read for the eigenfunctions ##Y_n##$$
Y_n(y) = n\pi\cosh(n\pi y)+\sinh(n\pi y)$$You don't need a constant multiple in front of them and there shouldn't be an ##x## in front of the ##\cosh## term. Similarly your eigenfunctions for ##X## are$$ X_n(x) = \sin(n\pi x)$$ Then you write your potential solution as$$ u(x,y) =\sum_{n=1}^\infty c_nX_n(x)Y_n(y)= \sum_{n=1}^\infty c_n\sin(n\pi x)(n\pi\cosh(n\pi y)+\sinh(n\pi y))$$Now you are ready for the Fourier Series solution to the last boundary condition. |
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