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Equation of tangent line (rec. form) to a polar curve!
Quesiton:
Find the rectangular form of the equation of the tangent line to the polar curve r=cos^3(theta) at the point corresponding to theta=pi/4
How to do that?
I mean finding it in RECTANGULAR FORM !
i know that
[tex]\frac{dy}{dx}=\frac{\frac{dr}{d\theta} sin(\theta)+rcos(\theta)}{\frac{dr}{d\theta} cos(\theta) - r sin(\theta)}[/tex]
I will calculate dy/dx at theta=pi/4 , and this is easy ..
The problem here is that, how can I find the equation of the tangent line in RECATNGULAR FORM ??
The equation of the tangent line is :
y-y1=m(x-x1)
m = the slope , and this one will be calculated by using the formula ..
but what about x1 and y1?
Homework Statement
Quesiton:
Find the rectangular form of the equation of the tangent line to the polar curve r=cos^3(theta) at the point corresponding to theta=pi/4
Homework Equations
The Attempt at a Solution
How to do that?
I mean finding it in RECTANGULAR FORM !
i know that
[tex]\frac{dy}{dx}=\frac{\frac{dr}{d\theta} sin(\theta)+rcos(\theta)}{\frac{dr}{d\theta} cos(\theta) - r sin(\theta)}[/tex]
I will calculate dy/dx at theta=pi/4 , and this is easy ..
The problem here is that, how can I find the equation of the tangent line in RECATNGULAR FORM ??
The equation of the tangent line is :
y-y1=m(x-x1)
m = the slope , and this one will be calculated by using the formula ..
but what about x1 and y1?