- #1
sapiental
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Hello,
evaluate the following integral:
[tex]\int x \sqrt{x^2+a^2}dx [/tex]
definite integral from 0 to a
what I did was
u = x^2 + a^2
du = 2xdx
1/2 sqrt(u)du
I just dropped the a^2 because we were finding the derivative of x but feel that it's very wrong.Any suggestions are much appreciated.
thanks.
evaluate the following integral:
[tex]\int x \sqrt{x^2+a^2}dx [/tex]
definite integral from 0 to a
what I did was
u = x^2 + a^2
du = 2xdx
1/2 sqrt(u)du
I just dropped the a^2 because we were finding the derivative of x but feel that it's very wrong.Any suggestions are much appreciated.
thanks.
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