Speed, Velocity, Acceleration, etc. at t=0

In summary, speed, velocity, and acceleration are defined as derivatives, which avoids the issue of being undefined at a specific time t=0. This is because they are instantaneous quantities, not averages. The formulas provided in the conversation are incorrect as they do not take into account the concept of derivatives.
  • #1
logan3
83
2
I was wondering how speed, velocity, acceleration and anything with a [itex]\Delta t[/itex] in the denominator are defined at [itex]\Delta t=0[/itex]? Other than approximating with limits, aren't they undefined?

Ex: [itex]{\vec{v_{avg}} = \frac{\vec{s}}{\Delta t}}[/itex], at t = 0 [itex]\Rightarrow {\vec{v_{avg}} = \frac{\vec{s}}{0}} \Rightarrow {\vec{v_{avg}}} = und.[/itex]

[itex]{\vec{a}} = \frac{\vec{v_{f}}-\vec{v_{i}}}{\Delta t}[/itex], at t = 0 [itex]\Rightarrow {\vec{a}} = \frac{\vec{v_{f}}-\vec{v_{i}}}{0} \Rightarrow {\vec{a}} = und.[/itex]

Thank-you
 
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  • #3
Well as mfb pointed out, they are defined by derivatives, and thus they are instantaneous and not average.
There is no average velocity/acceleration defined at a given time t=0, but in some interval Δt. So your formulas are wrong...

For [itex]\Delta t \rightarrow 0[/itex] you have:

[itex] a(t_0)= lim_{\Delta t \rightarrow 0} \frac{ u(t_{0}+ \Delta t) - u(t_{0})}{\Delta t}[/itex]
You can expand the [itex] u(t_{0}+ \Delta t)[/itex] around t0:
[itex] u(t_{0}+ \Delta t) \approx u(t_{0})+ \Delta t \frac{du(t)}{dt}|_{t=t_{0}}[/itex]
(you could try to write more terms in the series so avoid the approximation symbol, but later on you are going to take the limit of [itex]\Delta t \rightarrow 0[/itex] and so you see only the first power would survive-the rest would have [itex] \frac{(\Delta t)^{2}}{\Delta t} \rightarrow 0 [/itex] in that limit).

thus:

[itex] a(t_0)= lim_{\Delta t \rightarrow 0} \frac{ u(t_{0})+ \Delta t \frac{du(t)}{dt}|_{t=t_{0}} - u(t_{0})}{\Delta t}=\frac{du(t)}{dt}|_{t=t_{0}} [/itex]

As for a the acceleration (rate of change of velocity), a similar way is used for u, but with x instead of u (since it's the rate of change of position)

But there is no distinction between derivatives and limits... derivatives are mathematically defined by the first limit I wrote...now if you prefer listening to the name "derivative" instead of "limit" it's up to you. But all derivative properties are proved by their definition as limits.
 
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What is the difference between speed and velocity?

Speed is a measure of how fast an object is moving, while velocity is a measure of how fast an object is moving in a specific direction. Speed is a scalar quantity, while velocity is a vector quantity.

How is acceleration calculated at t=0?

Acceleration at t=0 is calculated by taking the change in an object's velocity over a specific time interval, divided by the time interval. This gives the instantaneous acceleration at t=0.

Can an object have a positive velocity and a negative acceleration at t=0?

Yes, an object can have a positive velocity and a negative acceleration at t=0. This means that the object is moving in a positive direction but is slowing down.

How does the force applied to an object affect its acceleration at t=0?

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. Therefore, the greater the force applied, the greater the acceleration at t=0 will be.

Can an object have a constant velocity and a non-zero acceleration at t=0?

No, if an object has a constant velocity, its acceleration at t=0 must be zero. This is because acceleration is defined as the change in velocity over time, so if the velocity is not changing, there is no acceleration.

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