- #1
ehrenfest
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Homework Statement
I can relate tau and X0 by:
[tex] \tau = \frac{X^0}{2 \sqrt{2} \alpha' p^+ } [/tex]
Why does that mean the angular frequency is
[tex] \frac{1}{2 \sqrt{2} \alpha' p^+ } [/tex]
?
Take this and plug it into the equations for [itex]X^{(2)}[/itex] and [itex]X^{(3)}[/itex].ehrenfest said:[tex] \tau = \frac{X^0}{2 \sqrt{2} \alpha' p^+ } [/tex]
The relationship between τ (period), X0 (amplitude), and angular frequency is given by the equation τ = 2πX0/ω, where ω represents the angular frequency.
You can calculate the period of a wave by using the equation τ = 2πX0/ω, where X0 is the amplitude and ω is the angular frequency.
No, in order to calculate the period of a wave using the equation τ = 2πX0/ω, you need to know the amplitude (X0) and the angular frequency (ω).
The unit of measurement for the period of a wave is typically seconds (s) since it represents the time it takes for one complete cycle of the wave.
Increasing the amplitude of a wave will result in a longer period, while increasing the angular frequency will result in a shorter period. This is because the period is directly proportional to the amplitude and inversely proportional to the angular frequency.