- #1
zooboodoo11
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1.Speedboat
A speedboat with a length of 10.2m and a mass of 247 kg is negotiaging a circular turn (radius = 33 m) around a buoy. During the turn, the engine causes a net tangential force of magnitude 521 N to be applied to the boat. The intial speed of the boat going into the turn is 4 m/sec.
a) What is the tangential acceleration of the boat, 2 sec into the turn?
aT = m/sec2 *
b) What is the tangential velocity of the boat, 2 sec into the turn?
vT = m/sec *
8.2 OK
c) What is the centripetal acceleration, 2 sec into the turn?
acen = m/sec2
528 NO
d) What is the total acceleration, 2 sec into the turn?
a = m/sec2
2. I got parts A and B, but for part C I tried using the formula: a(cp)= rw^2, i tried using the intitial velocity, 4 m/s and also tried using the calculated velocity from part b, 8.2 and neither are being accepted, am i making a conceptual mistake here in trying to apply this formula here?
3. Solution attempt: a=(33)(4)^2 / 33 and also, a=(33)(8.2)^2 / 33
I think I understand that the total will just be (At^2 + Acp^2) ^ .5 This is my first post so I hope this was in a clear enough format and not misplaced, thanks
A speedboat with a length of 10.2m and a mass of 247 kg is negotiaging a circular turn (radius = 33 m) around a buoy. During the turn, the engine causes a net tangential force of magnitude 521 N to be applied to the boat. The intial speed of the boat going into the turn is 4 m/sec.
a) What is the tangential acceleration of the boat, 2 sec into the turn?
aT = m/sec2 *
b) What is the tangential velocity of the boat, 2 sec into the turn?
vT = m/sec *
8.2 OK
c) What is the centripetal acceleration, 2 sec into the turn?
acen = m/sec2
528 NO
d) What is the total acceleration, 2 sec into the turn?
a = m/sec2
2. I got parts A and B, but for part C I tried using the formula: a(cp)= rw^2, i tried using the intitial velocity, 4 m/s and also tried using the calculated velocity from part b, 8.2 and neither are being accepted, am i making a conceptual mistake here in trying to apply this formula here?
3. Solution attempt: a=(33)(4)^2 / 33 and also, a=(33)(8.2)^2 / 33
I think I understand that the total will just be (At^2 + Acp^2) ^ .5 This is my first post so I hope this was in a clear enough format and not misplaced, thanks