- #1
fr33pl4gu3
- 82
- 0
2 cos( 2 x ) +sin( x ) = 2
sin(x)= 2 -2 cos (2x)
= 2 (1 - cos (2x))
= 2 (2 sin 2x)
= 4 sin2x
0= 4sin2x - sinx
= (sin x)(4sin2x-1)
The answer would be:
x = 0 and 0.25 (correct to 2 decimal place)
This is only partially correct, what's wrong??
sin(x)= 2 -2 cos (2x)
= 2 (1 - cos (2x))
= 2 (2 sin 2x)
= 4 sin2x
0= 4sin2x - sinx
= (sin x)(4sin2x-1)
The answer would be:
x = 0 and 0.25 (correct to 2 decimal place)
This is only partially correct, what's wrong??