- #1
username12345
- 48
- 0
Homework Statement
[tex]f(x, y) = \tan(x + y) \\
f_x = ?
[/tex]
Homework Equations
[tex]\frac{dy}{dx}\tan(x)= \sec^2 x[/tex]
The Attempt at a Solution
I set y as constant, so I said derivative of y = 0 then took derivative of tan as above. However the answer should be
[tex]f_x = \sec^2(x + y)[/tex]
Why is y included?