Good so far.licklecee said:Homework Statement
c) Calculate the current flowing when a 4 uF capacitor is connected across 240V 50 Hz supply ?
Homework Equations
XC = 1/(2πfC)
The Attempt at a Solution
XC = 1/(2πfC)
XC = 1/(2π 50*0.000004)
XC = 1/(2π* 0.0002)
XC = 1/(6.28* 0.0002)
XC = 1/ 0.001256
Nope. Do you see the error?XC = 0.001256
To calculate the current with a capacitor, you will need to use the formula I = C * dV/dt, where I is the current in amperes, C is the capacitance in farads, and dV/dt is the rate of change of voltage over time in volts per second.
A capacitor is an electronic component that is used to store electrical energy. It acts as a temporary storage device for charge and can release this stored energy when needed.
The capacitance value directly affects the amount of charge a capacitor can store, which in turn affects the current in a circuit. A higher capacitance means the capacitor can store more charge, resulting in a higher current when it is discharged.
No, a capacitor blocks the flow of direct current (DC) but allows alternating current (AC) to pass through it. This is because a capacitor stores energy in an electric field and blocks the flow of charge.
The time constant of a circuit with a capacitor can be calculated using the formula τ = R * C, where τ is the time constant in seconds, R is the resistance in ohms, and C is the capacitance in farads. The time constant is a measure of how quickly the capacitor charges or discharges in a circuit.