Comparing Forces and Power in a Pulley System: Help with Multiple Choice

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Power supplied is proportional to the product of the force and the velocity. Since block B is raised twice as fast, the power supplied must be twice that of block A. Therefore, FB must be equal to 2 times FA and PB must be equal to 2 times PA, making b) the correct answer. In summary, the conversation discusses two identical blocks being lifted at constant velocity by ropes over frictionless pulleys. Block B is raised twice as fast as Block A, causing the power supplied to be twice as much as well. The statement that correctly represents this scenario is b) FB = 2 FA; PB = 2 PA. The reasoning behind this answer is that power is proportional to the product of force and velocity,
  • #1
Phyzix
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Help please--multiple choice

Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?

a. FB = FA; PB = PA.
b. FB = FA; PB = 2 PA.
c. FB = 2 FA; PB = PA.
d. FB = 2 FA; PB = 2 PA.
e. PA = FA; PB = FB.
 
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  • #2
I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.
 
  • #3
Phyzix said:
Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?
Since you did not supply the diagram, we can only guess as to the arrangement of the pulleys. Assuming that both ropes run over single pulleys...

What does "constant velocity" tell you about the force needed? How does power depend upon speed?
 
  • #4
dextercioby said:
I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.

d?? I think it's a) - because it is at a constant velocity.
 
  • #5
futb0l said:
d?? I think it's a) - because it is at a constant velocity.

At equal velocities but different times,does it mean the same force??

Daniel.
 
  • #6
futb0l said:
d?? I think it's a) - because it is at a constant velocity.
Both d) and a) are half right. :smile: But more important than the answer is the reasoning behind it (as Daniel would say).
 
  • #7
Ooops - I meant b)... since power is F*v since b has 2v, then the power of b will be twice as much as a. Since it is at equillibrium then Fa = Fb.
 
  • #8
I agree: b) is the correct answer.
 
  • #9
Me too. Distance traveled by 1s : Distance traveled by 1s=1:s
Hence PA: PB=1:2
 

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