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oldandcurious
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Knowing the pressure to be 289.1 torr and boiling temperature of water at this pressure to be 75° C, what is the amount of energy needed to evaporate 1kg of water. Where can I find the table for different pressures?
The energy needed to evaporate water at 289.1 torr is the amount of energy required to change the state of water from liquid to gas at a pressure of 289.1 torr. It is a measure of the strength of the intermolecular forces between water molecules.
The energy needed to evaporate water at 289.1 torr can be calculated using the formula Q = m * ΔHv, where Q is the energy needed, m is the mass of water, and ΔHv is the enthalpy of vaporization of water at 289.1 torr. This value can be found in the table of pressures.
The energy needed to evaporate water at 289.1 torr is affected by several factors, including the pressure of the environment, the temperature of the water, and the strength of the intermolecular forces between water molecules. Other factors such as the surface area of the water and the presence of impurities can also impact the energy needed.
No, the energy needed to evaporate water at 289.1 torr is not a constant value. It can vary depending on the factors mentioned above. For example, at a higher pressure, more energy is needed to overcome the stronger intermolecular forces between water molecules. Similarly, at a higher temperature, less energy is needed as the molecules have more kinetic energy to break free from the liquid phase.
The table of pressures for the energy needed to evaporate water at 289.1 torr is useful for scientists and engineers working with water in various environments. It provides a reference for the energy needed under different pressure conditions, allowing for better understanding and control of the evaporation process. It can also be used to calculate the energy needed in specific scenarios and aid in the design of systems involving water evaporation.