Faraday's Calculation with 18 Volts: Why the Result is Inflated - Explanation

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In summary, the conversation is about an experiment related to electrochemistry and the calculation of Faraday. The question asks for an explanation of why using 18 volts instead of 9.0 volts results in a larger calculated value for Faraday. The response mentions the relationship between Faraday and voltage, suggesting that the increase in voltage leads to a larger value for Faraday.
  • #1
david2120
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If 18 volts are used in this experiment instead of 9.0 V, the value of the Faraday calculated is too large. Explain.

I don't get this question?
 
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  • #2
1. What subject is this - Electrochemistry ?

2. What class/grade are you in ?

3. What is the "experiment" ?

4. What are your thoughts ?

5. Please read the rules for this subforum (see my signature or the sticky thread)
 
  • #3
If 18 volts are used in this experiment instead of 9.0 V, the value of the Faraday calculated is too large. Explain



well it Faraday's equal to 1 C = J/V which we have 1V = J/C that's why its too large. Is it right?
 

What is Faraday's calculated?

Faraday's calculated refers to the calculated value of the Faraday constant, which is a measure of the electric charge per mole of electrons. It is represented by the symbol F and has a value of approximately 96,485 coulombs per mole.

Why is Faraday's calculated important?

Faraday's calculated is important because it is used in various calculations related to electrochemistry and electrolytic processes. It also helps in determining the amount of electric charge needed to produce a certain amount of chemical reaction.

How is Faraday's calculated determined?

Faraday's calculated is determined by dividing the Avogadro constant (6.022 x 10^23) by the number of electrons in one mole of electrons (6.242 x 10^18). This results in the Faraday constant of approximately 96,485 coulombs per mole.

What is the difference between Faraday's calculated and Faraday's constant?

Faraday's calculated is the theoretical value of the Faraday constant, while Faraday's constant is the experimentally determined value. Due to experimental errors and variations, the calculated and constant values may have slight differences.

What are some common applications of Faraday's calculated?

Faraday's calculated is used in various electrochemical calculations, such as determining the amount of electric charge required for electrolysis, calculating the amount of energy needed for a chemical reaction, and in the study of batteries and fuel cells.

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