How Do Double Angle Identities Simplify Trigonometric Equations?

In summary, the equation provided is asking to prove that (sin4x-sin2x)/sin2x = cos3x/cosx. The given identities to use are cos2x=cos^2x-sin^2x, cos2x=2cos^2x-1, cos2x=1-2sin^2x, and sin2x=2sinxcosx. The solution involves expanding the LHS and simplifying using the given identities. The final goal is to have all terms in terms of cosx.
  • #1
Jatt
7
0

Homework Statement


sin4x-sin2x/sin2x=cos3x/cosx


Homework Equations


sin2x = 2sinxcosx


The Attempt at a Solution



LS = sin(2x + 2x) - sin2x/sin2x
= sin2xcos2x + cos2xsin2x - sin2x/sin2x
= 2sin2xcos2x - sin2x/sin2x
This is where i get stuck...
I don't know what happens if you try to: 2sinx2x - sin2x or 2sin2x/sin2x, is that possible or not? Can you guys help me solve this question? Thanks.
 
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  • #2
Quick question you are to prove that
[tex]\frac{sin4x-sin2x}{sin2x}=\frac{cos3x}{cosx}[/tex]

?
 
  • #3
yup.
 
  • #4
I believe there are two more Relevant equations you need.
 
  • #5
dosen't matter i was able to solve it, but here's another problem which I'm now stuck with. [tex]cosx+cos2x+cos3x=cos2x(1+2cosx)[/tex].
I've tried many things with this problem, but always seem to get lost.
The only given identites which I'm given to use:
[tex]cos2x=cos^2x-sin^2x[/tex]
[tex]cos2x=2cos^2x-1[/tex]
[tex]cos2x=1-2sin^2x[/tex]
[tex]sin2x=2sinxcosx[/tex]
 
Last edited:
  • #6
OK, since you have to SOLVE and not prove...
if you expand the RHS you would see that the cos2x cancels out and you are left with

cos(x)+cos(3x)=2cos[itex]^2[/itex](x)

then expand out cos(3x) and see if anything gets simpler
 
  • #7
lol, sorry for not stating this, but i have to prove not solve.
 
  • #8
well then expand out the LHS
Recall that cos(3x)=cos(2x+x)
 
  • #9
yea then i get: cos2xcosx + sin2xsinx + cos2x + cosx
 
  • #10
cos2x=2cos^2(x)-1
and sin2x=2sinxcosx
cos^2(x)+sin^2(x)=1

expand out and find all in terms of cosx and hopefully it will work
 

1. What are double angle identities?

Double angle identities are trigonometric identities that involve the double of an angle. They are used to simplify expressions and solve equations involving trigonometric functions.

2. How do I use double angle identities?

To use double angle identities, you need to know the basic trigonometric identities and the formula for double angle identities. Then, you can substitute the double angle identity into the equation or expression and simplify it to solve for the unknown variable.

3. What is the formula for double angle identities?

The formula for double angle identities varies depending on the trigonometric function involved. For sine and cosine, the formula is: sin(2x) = 2sin(x)cos(x) and cos(2x) = cos^2(x) - sin^2(x). For tangent, the formula is: tan(2x) = 2tan(x) / (1-tan^2(x)).

4. How do I remember the double angle identities?

One way to remember the double angle identities is by using the acronym "SOH-CAH-TOA" which stands for sine = opposite/hypotenuse, cosine = adjacent/hypotenuse, and tangent = opposite/adjacent. In the double angle identities, the "SOH" part is doubled, while the "CAH" and "TOA" parts are squared and subtracted.

5. Can I derive double angle identities from other trigonometric identities?

Yes, double angle identities can be derived from other trigonometric identities. For example, the double angle identity for cosine can be derived from the Pythagorean identity (sin^2(x) + cos^2(x) = 1) and the sum and difference identities (cos(x+y) = cos(x)cos(y) - sin(x)sin(y)). However, it is more efficient to memorize the double angle identities for quick use in problem solving.

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