- #1
shawonna23
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A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius r. A passenger feels the seat of the car pushing upward on her with a force equal to three times her weight as she goes through the dip. If r = 16.0 m, how fast is the roller coaster traveling at the bottom of the dip?
I used the equation: v= square root of 3*r*g, but the answer was wrong. I don't know what other equation to use.
I used the equation: v= square root of 3*r*g, but the answer was wrong. I don't know what other equation to use.