## Determining invertibility of a matrix

Let A, B, C, D be matrices such that:

AB + CD = 0

and

B is invertible. Moreover, consider the dimension restrictions:

A(m x n), B(n x n), C(m x m), D(m x n)

If C is a square matrix, is there a way to show that it is also invertible with only the above conditions?
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 Recognitions: Science Advisor If you take A = D = 0, then AB + CD = 0 for any matrix C, so you can't prove C is invertible.
 A and D are non-zero matrices, forget to say.

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## Determining invertibility of a matrix

Take

$$A=\left(\begin{array}{cc} 1 & 1\\ 1 & 1 \end{array}\right), B=\left(\begin{array}{cc} 1 & 0\\ 0 & 1 \end{array}\right), C=\left(\begin{array}{cc} 1 & 1\\ 1 & 1 \end{array}\right), D=\left(\begin{array}{cc} -1 & 0\\ 0 & -1 \end{array}\right)$$
 A and D are rectangular, not square.
 Blog Entries: 8 Recognitions: Gold Member Science Advisor Staff Emeritus Take $$A=\left(\begin{array}{c} 1\\ 1\end{array}\right), B=\left(\begin{array}{c} 1 \end{array}\right), C=\left(\begin{array}{cc} 1 & 1\\ 1 & 1 \end{array}\right), D=\left(\begin{array}{c} -1\\ 0 \end{array}\right)$$
 The example you gave yields incompatible dimensions: AB is 1x2 and CD is 2x1.

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 Quote by allanmulin The example you gave have yields incompatible dimensions: AB is 1x2 and CD is 2x1.
I was editing. Check again.

You can really find these things for yourself.
 That's what I am trying to do! B and C should have the same dimension. A(m x n), B(n x n), C(m x m), D(m x n)

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