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Force of Gravity 
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#1
Dec3110, 04:18 PM

P: 9

1. The problem statement, all variables and given/known data
In this problem find the force of gravity of Al. Al is standing at the top of Mt. Everest at an elevation of 8,848 m. Al has a mass of 58 kg. The earth has a mass of 5.97e24 and a radius of 6.38e6m. What is the force of gravity acting on Al? 2. Relevant equations F = GMm/r^2 3. The attempt at a solution the dist. used to find F is from Al to the Earth's center ? so r = 8848+6.38e6 ?????? then plug in values F = G 58(5.97e24)/(8848+6.38e6)^2 F[tex]\approx[/tex]569.385 N? Is this right? I feel like i'm missing soemthing 


#2
Dec3110, 04:54 PM

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#3
Dec3110, 05:01 PM

P: 9

Hi! Thanks you for the welcome and your help. And just for reassurance, for r was i right to add the two values together?



#4
Dec3110, 06:32 PM

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Force of Gravity



#5
Dec3110, 10:34 PM

P: 9

Thanks so much!



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