Find Out When Acid & Metal Reactions Form One Water & CO2 or Carbonic Acid

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In summary, when doing reactions of acid and metal compound, it is important to carefully set up the reaction conditions to favor the maximum yield of product. The main reaction product can vary depending on factors such as pressure, temperature, and pH. In the case of forming one water and carbon dioxide or one carbonic acid, both ways are correct since one carbonic acid decomposes into one molecule of water and one molecule of carbon dioxide. However, the equilibrium point of the reaction may shift depending on the pressure and other factors, which can affect the yield of the desired product.
  • #1
pivoxa15
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When doing reactions of acid and metal compound, How do you know whether (one water and carbondioxide) or one carbonic acid will be formed? Since they have the same number of elements in the same proportion.
 
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Actually, one carbonic acid decomposes in one molecule of water and one molecule of carbon dioxide. Therefore, when doing chemical reactions you may right one carbonic acid or one molecule of water and one molecule of carbon dioxide, since both ways are correct.

:approve: :tongue:
 
  • #3
A reaction occurs because the resulting compound is more stable in some way, usually the main reaction product varies with varying conditions, pressure & temperature, pH etc. Also, there is rarley a clear cut line distinguishing the point at which one product is formed from another, it is a dynamic relationship or a equillibrium between reaction products.

Carefully setting up the reaction conditions to favour the maximum yield of product is what its about i guess.

With the example you gave i think it can be inferred from the fact that one of the products ( carbonic acid ) is the soluble form of carbon dioxide, and that as the pressure of the reaction conditions is raised, the equillibrium point of the reaction will shift away from the formation of the gas.

Also i believe that some products will hinder the yield by shifting the equillibrium point away from the optimum, as more CO2 is formed (in a closed system) the pressure would increase and hence the equillibrium point would eventually shift.

Maybe someone can give a better explanation this, or at least a more mathematical one :P
 

1. How does the reaction between acid and metal form water and CO2?

When an acid and a metal react, the metal atoms lose electrons to the hydrogen ions in the acid. As a result, the hydrogen ions are reduced to hydrogen gas (H2) and the metal atoms are oxidized, forming a metal ion. The hydrogen gas then combines with oxygen in the air to form water (H2O) and the metal ion combines with carbonate ions to form carbon dioxide (CO2).

2. Why does the reaction between acid and metal produce carbonic acid?

The production of carbonic acid (H2CO3) is a result of carbon dioxide (CO2) reacting with water (H2O) in the presence of an acid. This reaction forms carbonic acid, which is a weak acid that can easily dissociate into H+ and HCO3- ions.

3. What is the role of acid in this reaction?

The role of acid in this reaction is to provide hydrogen ions (H+) which can react with the metal atoms to form hydrogen gas (H2) and with the carbonate ions to form carbonic acid (H2CO3). The acid also helps to provide the necessary environment for the reaction to occur.

4. Which metals can react with acid to form water and CO2?

Metals that are more reactive than hydrogen, such as zinc, iron, and magnesium, can react with acid to form water and CO2. These metals have a higher tendency to lose electrons and form metal ions, making them suitable for this type of reaction.

5. How can you determine if a metal will react with acid to form water and CO2?

You can determine if a metal will react with acid to form water and CO2 by looking at its reactivity series. Metals that are above hydrogen in the reactivity series, such as zinc, iron, and magnesium, will react with acid to form water and CO2. However, metals that are below hydrogen, such as copper and silver, will not react with acid in this way.

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