- #1
alba_ei
- 39
- 1
Who can slove this one:
f(x) = [ln(x) {{1-e^(3x)}^3}] / [{1+e^(3x)}^3x]
f '(x) = ¿¿¿¿??
f(x) = [ln(x) {{1-e^(3x)}^3}] / [{1+e^(3x)}^3x]
f '(x) = ¿¿¿¿??
alba_ei said:I get stuck when I try to get the derivate of R(x).
The derivative of a function f(x) is denoted by f'(x) and represents the rate of change of the function at a specific point x.
To solve for f'(x), you can use the rules of differentiation such as the power rule, product rule, quotient rule, and chain rule. These rules allow you to find the derivative of a given function.
f'(x) is important in calculus because it allows us to understand the behavior of a function and its rate of change. It also helps us find maximum and minimum points of a function, which are crucial in optimization problems.
f'(x) tells us about the slope of the tangent line to the function at a specific point x. It also indicates whether the function is increasing or decreasing at that point.
Yes, f'(x) can be negative if the function is decreasing at a specific point x. In this case, the tangent line will have a negative slope, indicating a downward trend in the function.