|May29-12, 09:08 PM||#1|
Question about the Two-Body systems
Two blocks of identical material are connected by a light rope on a level surface. An applied force of 55N [right] causes the blocks to accelerate. While in motion, the magnitude of the force friction on the block is 44.1 N. Calculate the acceleration of the blocks.
20 kg|---------------------10kg | -----------------
(sorry about the diagram it looks ugly)
Fnet= Fapp - Ff
Fnet= 55 N - 44.1
a=10.9 N/30 kg which is equal to .363
Here's another question: Refer to the information above. The force on friction on the 10-kg block has a magnitude of 14.7 N.
a) calculate the tension in the rope connecting the two blocks
Ff= μ Fn
I know how to get the Ff2 this is what I did -----> Total Friction(44.1) - 14.7(Ff1 =Friction of 10Kg) = Ff2= 29.2 (20Kg)
My question is can you still answer the a) question without knowing the Friction of 10kg ? (Ff1) I got question a right but just wondering if you can still answer it without know the Friction of 10kg (Ff1).
|May30-12, 12:14 AM||#2|
I don't see where you arrive at the tension.
The easiest way is to think about the following ratios:
- frictional force, blk1 v. blk2 v. combined
- accelerational force, blk1 v. blk2 v. combined
- tension in RH rope v. tension in LH rope
|acceleration, fnet, friction, two blocks|
|Similar Threads for: Question about the Two-Body systems|
|Many-Body Systems||Classical Physics||5|
|Visualizing Astrophysical N-body Systems, John Dubinski||Cosmology||3|
|2-body or more orbit systems?||Astrophysics||3|
|PASC:45.50.Jf Few- and many-body systems||General Physics||1|