- #1
NATSALANE
- 10
- 0
given the cutoff potential (0.25 V) and wavelength (578 nm), how do i find the maximum kinetic energy of the electrons ejected from photoelectrif surface, in both eV and J?
my guess is,
KE = e Vo
= (1.6 x 10-19) x (0.25 V)
= 4.0 x 10-20 J
but if i convert that to eV, i get the same value as the cutoff potential - that can't be right.
can someone help me?
my guess is,
KE = e Vo
= (1.6 x 10-19) x (0.25 V)
= 4.0 x 10-20 J
but if i convert that to eV, i get the same value as the cutoff potential - that can't be right.
can someone help me?