Proving Exponential Inequalities for Positive Real Numbers

  • Thread starter julypraise
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In summary, to prove that a^x > 0 for all x in R where a > 1, and a^y > 1 for all y > 0, and 0^b = 0 for b > 0, you can use the following steps: 1) Prove it for all natural numbers x using induction. 2) Use the property a^{-x} = (a^x)^{-1} to extend the proof for all integers. 3) Use the property a^{m/n} = \sqrt[n]{a^m} and the continuity of a^x to prove it for all rational numbers. 4) Finally, restrict the value of b to be greater than
  • #1
julypraise
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(Sorry for the wrong title!)

Let a>1 (a in R). Then how do you prove for all x in R, a^x > 0 ?

And also that a^y>1 for all y>0, how do you prove?

And also how do you prove that 0^b = 0 when b is a real number?

(For me this is so difficult. So please just help me. Enough hints will suffice, no full solution.)
 
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  • #2
This depends on what you can use. I would prove it by the following scheme:

1) First prove it for all natural numbers x (by induction).

2) Use [itex]a^{-x}=(a^x)^{-1}[/itex] to prove it for all integers.

3) Use [itex]a^{m/n}=\sqrt[n]{a^m}[/itex] to prove it for all rational numbers.

4) Use continuity of [itex]a^x[/itex] to prove it for all real numbers.
 
  • #3
Could you help me bit more on proving the part 3)?

So by the theorem in Rudin's Mathematical Analysis in page 10 thm 1.21, I can prove this right?
 
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  • #4
julypraise said:
Third problem:

And also how do you prove that 0^b = 0 when b is a real number?

b must be restricted, as in b > 0, so that 0^b is not

undefined and/or is not indeterminate.
 
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1. What does x^a >= 1 mean?

X^a is a mathematical notation that represents the exponential function, where x is the base and a is the exponent. The notation x^a >= 1 means that the result of x^a is greater than or equal to 1.

2. How do you prove x^a >= 1 for all values of x and a?

To prove x^a >= 1 for all values of x and a, we can use mathematical induction. This method involves proving that the statement is true for a base case, usually a=0 or a=1, and then showing that if it is true for any value of a, it is also true for a+1. This process is repeated until the statement is proven for all values of a.

3. Can you provide an example to illustrate x^a >= 1?

For example, if x=2 and a=3, then 2^3 = 8, which is greater than 1. Therefore, x^a >= 1 is true for this specific case.

4. Is x^a >= 1 always true for positive values of x and a?

Yes, x^a >= 1 is always true for positive values of x and a. This is because when x is positive, any positive exponent a will result in a positive value, which is always greater than or equal to 1.

5. Why is it important to prove x^a >= 1?

Proving x^a >= 1 is important because it is a fundamental concept in mathematics and is used in many fields such as physics, engineering, and economics. It also helps to understand the behavior of exponential functions and their relationship to other mathematical functions.

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