Problem involving incline, spring and friction

In summary, the problem involves a block of mass 2.00 kg on a rough incline at an angle of 37.0° connected to a spring with a spring constant of 100 N/m. The block is released from rest and moves 18.6 cm down the incline before coming to rest. The goal is to find the coefficient of kinetic friction between the block and incline. To solve this, one can use energy conservation and set the initial potential energy from the spring and gravity equal to the final energy from friction. By solving for the coefficient of friction, u, one can determine the answer to the problem.
  • #1
cgotu2
6
0
I've been trying everything to solve this problem: It says:

A block of mass m = 2.00 kg situated on a rough incline at an angle of = 37.0° is connected to a spring of negligible mass having a spring constant of 100 N/m. The pulley is frictionelss. The block is released from rest when the spring is unstretched. The block moves 18.6 cm down the incline before coming to rest. Find the coefficient of kinetic friction between block and incline.

Please help me, I already tried to determine the force exerted by the spring in order to get the coefficent, but my answer is incorrect. I'm not sure how to relate all aspects of the problem. I tried to determine the PE of the spring, but how do i use that? (PE = 1/2kx^2)
 
Last edited:
Physics news on Phys.org
  • #2
You can use energy conservation to solve this problem. While the block is at rest on the incline, it has potential energy from the spring .5*k*x^2 and from gavitational potential energy m*g*h (where h equals d*sin(angle) ). At the end it has only frictional energy u*m*g*d*cos(angle).

The key to solving this is to first draw a diagram and then set initial energy equal to final energy. You should solve for u (the coefficient of friction) in this manner.
 
  • #3


First, let's break down the problem into smaller parts to make it easier to solve. We know that the block is on an inclined plane, so there will be two forces acting on it: the force of gravity pulling it down the incline and the normal force from the incline pushing it back up. Since the block is at rest before the spring is released, we can assume that these forces are equal and opposite, canceling each other out.

Next, we need to consider the spring. When the block is released, the spring will start to stretch and exert a force on the block. This force will act in the opposite direction of the block's motion. We can use Hooke's Law (F = -kx) to determine the force exerted by the spring, where k is the spring constant and x is the distance the spring has stretched.

Now, let's look at the motion of the block. We know that it moves 18.6 cm down the incline before coming to rest, so we can use this distance to determine the work done by the spring (W = Fd). We can also use the work-energy theorem (W = ΔKE) to find the kinetic energy of the block at this point.

Since the block eventually comes to rest, we know that all of its kinetic energy has been converted to other forms, such as potential energy and heat due to friction. We can use the conservation of energy (KEi + PEi + W = KEf + PEf) to relate the initial and final energies of the block. At this point, we can use the potential energy equation (PE = mgh) to solve for the coefficient of kinetic friction (μk).

In summary, to solve this problem, we need to consider the forces acting on the block, the work done by the spring, and the conservation of energy. It may also be helpful to draw a free body diagram to visualize the forces acting on the block. Keep in mind that the coefficient of kinetic friction represents the ratio of the force of friction to the normal force, so it can also be calculated using the equation μk = Ff/N. I hope this helps you solve the problem. Good luck!
 

1. What is the relationship between the incline angle and the force required to move an object up the incline?

The incline angle affects the force required to move an object up the incline. As the angle increases, the force required to move the object also increases due to the increase in the component of the object's weight parallel to the incline. This relationship can be represented by the equation F = mg*sinθ, where F is the force required, m is the mass of the object, g is the acceleration due to gravity, and θ is the incline angle.

2. How does the spring constant affect the motion of an object on an incline?

The spring constant, or the stiffness of the spring, affects the motion of an object on an incline by determining the force exerted by the spring on the object. A higher spring constant means a stiffer spring and therefore a greater force exerted on the object. This can affect the acceleration and velocity of the object as it moves up or down the incline.

3. What role does friction play in an incline and spring problem?

Friction plays a significant role in incline and spring problems as it can affect the motion of the object and the forces acting on it. Friction between the object and the incline can cause a decrease in velocity, and friction between the spring and the object can affect the force exerted by the spring. It is important to consider the effects of friction when solving these types of problems.

4. How do you determine the net force acting on an object on an incline with a spring attached?

The net force acting on an object on an incline with a spring attached can be determined by considering all the forces acting on the object. This includes the weight of the object, the force exerted by the spring, and the force of friction. The net force can be calculated using the equation Fnet = ma, where Fnet is the net force, m is the mass of the object, and a is the acceleration of the object.

5. How can the energy conservation principle be applied to an incline and spring problem?

The energy conservation principle, which states that energy cannot be created or destroyed, can be applied to an incline and spring problem by considering the potential and kinetic energy of the object. As the object moves up or down the incline, its potential energy (due to its position) and kinetic energy (due to its motion) will change. By equating these energies at different points in the object's motion, one can solve for unknown variables such as velocity or displacement.

Similar threads

  • Introductory Physics Homework Help
Replies
27
Views
6K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
24
Views
999
  • Introductory Physics Homework Help
Replies
20
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
437
  • Introductory Physics Homework Help
Replies
15
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
357
  • Introductory Physics Homework Help
Replies
13
Views
926
  • Introductory Physics Homework Help
Replies
33
Views
2K
Back
Top