- #1
eljose
- 492
- 0
Check the webpage..
http://arxiv.org/ftp/math/papers/0402/0402259.pdf
specially the part of Abel-Plana formula as a renormalization tool...
[tex] \zeta(-m,\beta)-\beta ^{m}/2- i\int_{0}^{\infty}dt[ (it+\beta )^{m}-(-it+\beta )^{m}](e^{2 \pi t}-1)^{-1}=\int_{0}^{\infty}dpp^{m} [/tex]
valid for every m>0 so renormalization for gravity can be possible. :uhh:
[tex] \zeta(-m,\beta)-\beta ^{m}/2- i\int_{0}^{\infty}dt[ (it+\beta )^{m}-(-it+\beta )^{m}](e^{2 \pi t}-1)^{-1}=\int_{0}^{\infty}dpp^{m} [/tex]
http://arxiv.org/ftp/math/papers/0402/0402259.pdf
specially the part of Abel-Plana formula as a renormalization tool...
[tex] \zeta(-m,\beta)-\beta ^{m}/2- i\int_{0}^{\infty}dt[ (it+\beta )^{m}-(-it+\beta )^{m}](e^{2 \pi t}-1)^{-1}=\int_{0}^{\infty}dpp^{m} [/tex]
valid for every m>0 so renormalization for gravity can be possible. :uhh:
[tex] \zeta(-m,\beta)-\beta ^{m}/2- i\int_{0}^{\infty}dt[ (it+\beta )^{m}-(-it+\beta )^{m}](e^{2 \pi t}-1)^{-1}=\int_{0}^{\infty}dpp^{m} [/tex]
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