- #1
mahmoud2011
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The Problem is when I Compute the Inverse I have to solutions
[itex]sech^{-1}(x) = ln(\frac{1\pm \sqrt{1-x^{2}}}{x}) : 0<x\leq 1 [/itex]
And this not function which of them I will choose
Another Question is how can I prove without the graph that csch (x) is one - to -one
thanks
[itex]sech^{-1}(x) = ln(\frac{1\pm \sqrt{1-x^{2}}}{x}) : 0<x\leq 1 [/itex]
And this not function which of them I will choose
Another Question is how can I prove without the graph that csch (x) is one - to -one
thanks
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