Solving a fourth order PDE by finite difference method by matlab

[tanma_amnat]

Homework Statement

how can i solve this problem by MATLAB?
pls help me

A (d4y/dx4) - B(d2y/dt2) = Cy

A=E*I

B=p*sin(w*t)

c=p*w2




conditions are

1.at x=0, dy/dx=0

2.at x=0,y=0

3.at x=L d2y/dx2=0

4. at x=L d3y/dx3=p (p is a function of t here)

x=0 and x=L are the two boundaries

pls tell me how can i slove it in MATLAB

Homework Equations

conditions are

1.at x=0, dy/dx=0

2.at x=0,y=0

3.at x=L d2y/dx2=0

4. at x=L d3y/dx3=p (p is a function of t here)

x=0 and x=L are the two boundaries

The Attempt at a Solution

i tried to solve it this way but not sure wheather it was right

...............

format long;
clc;
clear all;
m=10;
n=100;
l=.5;
time=input('t = ');
h=l/m;
k=time/n;
z=h/k;
r=m-1;
d=.05;
w=.1;
q=1;
p=1000;
E=207e9;
I=(3.1416*d^4)/64;

tt=[k:k:time];

T=(p*sin(w*tt(1,)*(1/k^2);
A=E*I*k^2/h^4;
C=p*w^2*k^2;

a=zeros(n*r);
b=zeros(n*r,1);
b(:,1)=q;

i=1;t=1;

for e=1:r
if i==1
a(e,i)=A-C;
a(e,i+1)=-4*A;
a(e,i+2)=6*A;
a(e,i+3)=-4*A;
a(e,i+4)=A;

a(e,r+i)=-T(t);
a(e,2*r+i)=2*T(t);
a(e,3*r+i)=-T(t);
elseif i==r
a(e,i)=A-C;
a(e,i-1)=-4*A;
a(e,i-2)=6*A;
a(e,i-3)=-4*A;
a(e,i-4)=A;

a(e,r+i)=-T(t);
a(e,2*r+i)=2*T(t);
a(e,3*r+i)=T(t);
else
a(e,i)=6*A-C;
a(e,i+1)=-4*A;
if (i+2)<=r
a(e,i+2)=A;
end
a(e,i-1)=-4*A;
if (i-2)>0
a(e,i-2)=A;
end
a(e,r+i)=-T(t);
a(e,2*r+i)=2*T(t);
a(e,3*r+i)=-T(t);
end
i=i+1;
end

s=0;i=1;t=2;

for e=(r+1):((n*r)-r)
if i==1
a(e,(t-1)*r+i)=A+2*T(t)-C;
a(e,(t-1)*r+i+1)= -4*A;
a(e,(t-1)*r+i+2)= 6*A;
a(e,(t-1)*r+i+3)= -4*A;
a(e,(t-1)*r+i+4)=A;
a(e,t*r+i)=-T(t);
a(e,(t-2)*r+i)=-T(t);
elseif i==r
a(e,(t-1)*r+i)=A-C+2*T(t);
a(e,(t-1)*r+i-1)= -4*A;
a(e,(t-1)*r+i-2)= 6*A;
a(e,(t-1)*r+i-3)= -4*A;
a(e,(t-1)*r+i-4)=A;

a(e,t*r+i)=-T(t);
a(e,(t-2)*r+i)=-T(t);
else
a(e,(t-1)*r+i)=6*A+2*T(t)-C;
a(e,(t-1)*r+i+1)=-4*A;
if (i+2)<=r
a(e,(t-1)*r+i+2)=A;
end
a(e,(t-1)*r+i-1)=-4*A;
if (i-2)>0
a(e,(t-1)*r+(i-2))=A;
end
a(e,(t*r)+i)=-T(t);
a(e,(t-2)*r+i)=T(t);
end
s=s+1;
if s==r
t=t+1;
s=0;
i=1;
else
i=i+1;
end
end

i=1;t=n;
for e=(n*r-r)+1:(n*r)
if i==1
a(e,(t-1)*r+i)=A-C;
a(e,(t-1)*r+i+1)= -4*A;
a(e,(t-1)*r+i+2)= 6*A;
a(e,(t-1)*r+i+3)= -4*A;
a(e,(t-1)*r+i+4)=A;

a(e,(t-2)*r+i)=-T(t);
a(e,(t-3)*r+i)=2*T(t);
a(e,(t-4)*r+i)=-T(t);

elseif i==r
a(e,(t-1)*r+i)=A-C;
a(e,(t-1)*r+i-1)= -4*A;
a(e,(t-1)*r+i-2)= 6*A;
a(e,(t-1)*r+i-3)= -4*A;
a(e,(t-1)*r+i-4)=A;

a(e,(t-2)*r+i)=-T(t);
a(e,(t-3)*r+i)=2*T(t);
a(e,(t-4)*r+i)=-T(t);
else
a(e,(t-1)*r+i)=6*A;
a(e,(t-1)*r+i+1)=-4*A;
if (i+2)<=r
a(e,(t-1)*r+i+2)=A-C;
end
a(e,(t-1)*r+i-1)=-4*A;
if (i-2)>0
a(e,(t-1)*r+(i-2))=A;
end
a(e,(t-2)*r+i)=-T(t);
a(e,(t-3)*r+i)=2*T(t);
a(e,(t-4)*r+i)=-T(t);
end
i=i+1;
end

x=a\b;

v=zeros(n,r);
y=1;
for i=1:r
for j=1:n
v(i,j)=x(y);
y=y+1;
end
end
v;
%plot(v)
plot(rot90(v))

............
i could use only two conditions

1.at x=0, dy/dx=0

2.at x=0,y=0

seeking your advice

 

[lippyka]

.The Attempt at a SolutionYou can use MATLAB's numerical integration functions to solve this problem. First, you need to create a function that describes the differential equation:function dydx = diffeq(x,y,A,B,C)dydx = [A*(d4y/dx4)-B*(d2y/dt2)];endThen, you need to set up the boundary conditions, which are given in the problem statement: x0 = 0; % Boundary condition at x=0y0 = 0; % Boundary condition at x=0xL = L; % Boundary condition at x=Ld2y_xL = 0; % Boundary condition at x=Ld3y_xL = p; % Boundary condition at x=LFinally, you can use MATLAB's ode45 function to solve the differential equation numerically: [x,y] = ode45(@(x,y) diffeq(x,y,A,B,C), [x0 xL], [y0 d2y_xL d3y_xL]);