Solve Problem: Let f (x, y)=xye^(− ((x−a)^2)− ((y−b)^ 2))

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In summary, the conversation discusses solving problems involving the function f(x, y) = xye^(-(x-a)^2-(y-b)^2) and its gradient. The main question is in which direction to go from the point (a, b) to increase the function values as quickly as possible. The conversation also mentions finding an equation for the tangent plane to the surface z=f(x, y) at the point (a, b, ab) and using the differential of f to approximate the function value at (9a/10, 6b/5). Finally, the conversation asks for the points where the tangent plane is horizontal. The person asking for help is reminded to show their work and corrects a typo in their
  • #1
electricman
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Hi,

I have some problems to solve this:

Let f (x, y)=xye^(− ((x−a)^2)− ((y−b)^ 2)). In which direction, one will go from the point (a, b) in the definition amount if one wants to that the function values will increase so quickly as possible? Decide an equation for key planet to the surface z=f (x, y) in the point (a, b, ab). Use differential to f in order to calculate a close value to f (9a/10, 6b/5). In which points, key planet is to the surface z=f (x, y) horizontal?

Anyone who knows how to solve this?
 
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  • #2
electricman said:
Hi,

I have some problems to solve this:

Let f (x, y)=xye^(− ((x−a)^2)− ((y−b)^ 2)). In which direction, one will go from the point (a, b) in the definition amount if one wants to that the function values will increase so quickly as possible? Decide an equation for key planet to the surface z=f (x, y) in the point (a, b, ab). Use differential to f in order to calculate a close value to f (9a/10, 6b/5). In which points, key planet is to the surface z=f (x, y) horizontal?

Anyone who knows how to solve this?
Those are all basic 'grad f' problems. Do you know why? What is special about the direction grad f points. Please show SOME work if you expect help. Oh, and I think you mean "tangent plane" instead of "key planet".
 

1. How do I solve for the critical points of this function?

To solve for the critical points of f(x, y), we need to take the partial derivatives of f with respect to x and y and set them equal to 0. This will give us a system of equations that we can solve for the critical points.

2. How do I find the maximum or minimum value of this function?

To find the maximum or minimum value of f(x, y), we can use the second derivative test. We first find the critical points of the function and then evaluate the second derivative at those points. If the second derivative is positive, the point is a minimum; if it is negative, the point is a maximum.

3. What is the significance of the parameters a and b in this function?

The parameters a and b represent the center of the function, which is also the location of the maximum value. These values affect the shape and position of the graph, and changing them will result in a different maximum value.

4. Can this function be applied to real-world problems?

Yes, this function can be applied to real-world problems such as modeling population growth or the distribution of resources. The parameters a and b can represent the location of a specific population or resource, and the maximum value can represent the most optimal location for that population or resource.

5. Can this function be extended to more than two variables?

Yes, this function can be extended to more than two variables by adding additional terms to the function. However, the process of finding critical points and maximum/minimum values becomes more complex as the number of variables increases.

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