- #1
salman213
- 302
- 1
1. http://img503.imageshack.us/img503/1480/21144697lh1.jpg [/URL]
3.
Pmax = Vth^2/4Rth
so I am guessing i treat R as the Rth and find Rth.
to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth.
my mesh analysis equations:
Vx + 1 =0
-1 + i2 + 2Vx=0
therefore i2 = 3
2i3 + 1 =0
i3 =-1/2
i3 + i1 = i2
therefore
i1 = 1/2 + 3
i1 = 7/2
Rth = (1)/(7/2) = 2/7
now to find Vth
I used nodal analysis and mesh analysis both
1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0
Solving I found Vth = 15 V
Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W
CAN SOMEONE PLEASE CHECK THAT!
thank you!
3.
Pmax = Vth^2/4Rth
so I am guessing i treat R as the Rth and find Rth.
to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth.
my mesh analysis equations:
Vx + 1 =0
-1 + i2 + 2Vx=0
therefore i2 = 3
2i3 + 1 =0
i3 =-1/2
i3 + i1 = i2
therefore
i1 = 1/2 + 3
i1 = 7/2
Rth = (1)/(7/2) = 2/7
now to find Vth
I used nodal analysis and mesh analysis both
1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0
Solving I found Vth = 15 V
Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W
CAN SOMEONE PLEASE CHECK THAT!
thank you!
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