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Bryon
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My question here is do I have the correct limits of integration? At first I thought it would be from pi/10 to 3pi/10 but I have a feeling that those are incorrect.
Find the area of one petal of the polar function r(x) = cos(5x)
integral[alpa to beta] .5* r(x)^2dx
cos(5x) = 0 when x = (1/5)*pi/2 = pi/10
This means that the limits of integration are pi/10 and -pi/10
integral (.5*cos(5x))dx = 1/4x - (sin(5x)/20) from pi/10 to -pi/10
Homework Statement
Find the area of one petal of the polar function r(x) = cos(5x)
Homework Equations
integral[alpa to beta] .5* r(x)^2dx
The Attempt at a Solution
cos(5x) = 0 when x = (1/5)*pi/2 = pi/10
This means that the limits of integration are pi/10 and -pi/10
integral (.5*cos(5x))dx = 1/4x - (sin(5x)/20) from pi/10 to -pi/10