- #1
Lucretius
- 152
- 0
I was doing the Inverse Square Law, trying to find out g at the surface of the Earth.
[tex]\frac{4\pi(G)(M)}{4\pi(r)^2}=g[/tex]
G = Gravitational Constant
M = Mass of Earth
[tex]\frac{4\pi(6.67x10^-11)(6.0x10^24)}{4\pi(6378^2)}=g[/tex]
[tex]g=9,838,028[/tex]
If I did the math right, can anyone tell me what this value means? I don't know what gravity is supposed to be quantified as. Can't be acceleration unless I did the math wrong (which I wouldn't doubt I did.) Any help is appreciated.
[tex]\frac{4\pi(G)(M)}{4\pi(r)^2}=g[/tex]
G = Gravitational Constant
M = Mass of Earth
[tex]\frac{4\pi(6.67x10^-11)(6.0x10^24)}{4\pi(6378^2)}=g[/tex]
[tex]g=9,838,028[/tex]
If I did the math right, can anyone tell me what this value means? I don't know what gravity is supposed to be quantified as. Can't be acceleration unless I did the math wrong (which I wouldn't doubt I did.) Any help is appreciated.