- #1
moleman1985
- 20
- 0
Hello, I have the following problem and am unsure how to solve it, although I believe the heat of dissolution to be -71.76kJ/mol, but I can only see how this would help me if my acid was infinetly dissoluted which is not the case so I need to know how the calculate a temperature rise when this is not the case.
My acid starts off at 98% wt. total wieght 115.985041 kg, (1158.9 moles H2SO4, and 128.8 moles H2O).
The acid ends up at 75% wt. total weight 151.55284 kg, (1158.9 moles H2SO4, and 2103.1 moles H20).
Both the acid and water initial temps can be taken as 30oC,
So basically 115.98kg of 98% wt. H2SO4 at 30oC, with 35.5kg water at 30oC
My acid starts off at 98% wt. total wieght 115.985041 kg, (1158.9 moles H2SO4, and 128.8 moles H2O).
The acid ends up at 75% wt. total weight 151.55284 kg, (1158.9 moles H2SO4, and 2103.1 moles H20).
Both the acid and water initial temps can be taken as 30oC,
So basically 115.98kg of 98% wt. H2SO4 at 30oC, with 35.5kg water at 30oC