- #1
muddyjch
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Homework Statement
Find the area of the region inside: r = 9 sinθ but outside: r = 1
Homework Equations
The Attempt at a Solution
r = 9 sinθ is a circle with center at (0, 4/2) and radius 4/2 while r= 1 is a circle with center at (0, 0) and radius 1. The two curves intersect where sin(θ)= 1/9. For 0 ≤ θ ≤ π that is satified by θ=sin^-1(1/9) and θ=π-sin^-1(1/9).
This is where i get lost setting up the differential for the area?