The Lorentz transformation matrix properties

Muphrid

The matrix's components may make a nice "symmetric" pattern, but the operator is not equal to its adjoint, therefore it is not symmetric in the strictest sense of linear algebra.

Mesmerized

thanks, Muphrid, but I guess you're a little too clever for me for now. We'll talk after some half a year :)

And that matrix from Weinberg's book I was talking about, it turned out that it was written really wrong, but in the russian version, which I'm reading. In the original it's perfectly right.