Push-up as Lever - How Much Weight Moved?

In summary: F=ma. But if you are lifting the weight at one extreme of the body, then the equation becomes F=ma (weight at one end of the body).
  • #1
greg333
5
0
I'm trying to determine approximately how much (percentage) of an athlete's body weight is moved when doing a push-up. I know it's a second class lever, but the lever itself is the load, and worse, the load is not evenly distributed along the length. I know approximate body segment weights, but I'm not sure how to proceed.

Any ideas? Thanks.
 
Physics news on Phys.org
  • #2
Key points:
  • First of all, don't worry about the load/resistance being the lever itself. All levers with mass present some sort of resistance.
  • The work needed to move a mass on the lever is a product of both it's distance from the fulcrum (hinge, toes in this case) and the weight itself. A 50kg mass in the center of a 2nd-class lever presents the same work load as a 100kg mass placed on the very end.

Now, I'm not sure what you mean by what percentage of weight must be lifted. Do you mean "what is the ratio of force needed to do a pushup to the person's bodyweight?".

That depends on the person's weight distribution. If all their weight is directly on the shoulders, it's 100%. If all the weight is directly on the toes, it is 0%.

I'll leave you with that for now.
Hint: It has a lot to do with the center of mass's position along the lever. If the center of mass is right smack in the middle, the person must apply a force equal to 1/2 his/her bodyweight.
 
Last edited:
  • #3
What I meant by percent moved is, say I weight 85kg - that 85 kg is obviously not all located at my shoulders, although the majority of it is pretty close. In a full push-up (sternum travels from floor to 20 cm above the floor), how much of that 85kg was moved that 20 cm?

I can figure out pretty well the weight distribution - e.g. thighs are about 14.5% of body weight, torso about 45%, etc.

Maybe I'm approaching it incorrectly... Not too sure anymore.

Ultimately, I want to be able to approximate the work and power of a number of push-ups at a certain body weight.
 
  • #4
First, approximate a point along the body at which you calculate (or speculate;)) the center of mass is. I do not know what your approximations are, so I will make up a simple distribution to use as an example. Say your legs (first 40% of length) are 20% of bodyweight. Say your midsection (middle 20% of length) is 50% of your bodyweight. Then your upper-body is 30% of your weight.

With these numbers, your center of mass would be at 52% of the length of your body, counting up from the toes. In other words, this is the "balance point", or the point along the length of your body at which the weight is equal on both sides of the point.
Once you figure out the center of mass, you can treat the whole body as a single mass resting on that point.

Perhaps a diagram will help:
http://img452.imageshack.us/img452/2982/physicsdiagram3it.jpg"

In this example, a person 85kg, 182cm tall is lifting one extreme end of his body 20cm off the ground. If we speculate that the center of mass is at 100cm from his feet, we simply figure out the work needed to lift his mass the distance that his mass gets lifted.

Since 100cm (center of mass measured from feet) is approximately 11/20 of his body length, then the distance his center of mass is lifted is 11/20 of 20cm, or 11cm. Work done is simply this distance times force (weight of body).
 
Last edited by a moderator:
  • #5
Awesome. That helps completely.
Thanks a lot.
by the way, your estimation of center of mass is pretty good - 55-56% of height is the general rule among kinesiologists, et al.
 
  • #6
Glad I could help.
 
  • #7
Could you explain this to a non-technical person? It seems to me, the formula works if you are lifting the weight at the center of mass. But one is lifting at one extreme of the body. How is that factored in or how do you calcuate that? Apologies, but I'm not good with math. Thanks!
 
  • #8
I did a pushup on a bathroom scale and it read 80% of my weight. I only have one scale and it would be more accurate with two scales. I think 75% would be close to the number.
 
  • #9
Thanks for the idea, nucleas. I did the same thing and got about 70% of my total weight. That could just mean I have less upper body mass than you.
 
  • #10
ben357 said:
Could you explain this to a non-technical person? It seems to me, the formula works if you are lifting the weight at the center of mass. But one is lifting at one extreme of the body. How is that factored in or how do you calcuate that? Apologies, but I'm not good with math. Thanks!

The formula doesn't work only if you lift the weight at the center of mass, but rather: the formula of lifting from your center of mass is a simplification of real situation. But while it's a simplification, the answer will be exactly the same (if you determine the center of mass correctly).



The alternative is to cut the body - on paper - in an arbitrary high amount of small parts (the more the better) and calculate the contribution of lifting each of those to the corresponding heights, and sum all of them. But much easier is to average all of those parts to one center of mass, multiply that by the height of the center of mass, et voila!
 
  • #11
Hi All,

Sorry to bump this thread, but I had a question:

If I were to measure the amount of water I dsiplace when fully submerged, and then slowly lower myself until 50% of that original displacement had been reched; would that depth be my midpoint for use in determining the amount of weight I move during a pushup?

Also, how does the formula change for pull-ups?
 

1. How does the concept of a lever apply to push-ups?

The concept of a lever applies to push-ups in the sense that the body is acting as a lever, with the fulcrum being the hands and the weight being moved being the body itself. The arms and shoulders act as the effort force, while the ground acts as the resistance force.

2. Can you explain the principle of mechanical advantage in relation to push-ups?

The principle of mechanical advantage in push-ups refers to the ability to move a larger weight with less effort. By positioning the hands closer together or elevating the feet, the lever arm is shortened and the mechanical advantage is increased, making the push-up easier to perform.

3. How much weight is actually being moved during a push-up?

The weight being moved during a push-up is equivalent to the body weight being lifted off the ground. For example, if a person weighs 150 pounds, they are moving 150 pounds during each push-up.

4. Does the weight distribution of the body affect the difficulty of a push-up?

Yes, the weight distribution of the body can affect the difficulty of a push-up. Placing more weight on the upper body, such as by elevating the feet, can increase the difficulty of the push-up as it requires more effort from the arms and shoulders.

5. Is it possible to add additional weight to a push-up to increase the difficulty?

Yes, it is possible to add additional weight to a push-up to increase the difficulty. This can be done by using a weighted vest, placing weights on the back or shoulders, or using resistance bands. This increases the overall weight being moved and requires more effort from the muscles.

Similar threads

Replies
11
Views
1K
Replies
21
Views
1K
Replies
5
Views
1K
Replies
4
Views
651
Replies
8
Views
2K
Replies
25
Views
5K
Replies
8
Views
3K
Back
Top