- #1
danculax
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lim (sinx-cosx)/(pi-4x) where x-->pi/4
Hi! Could someone help me to solve this problem without using L'Hospital rule? Any hint would be splendid...
lim (sinx-cosx)/(pi-4x)
x-->pi/4
Thanks in advance!
Hi! Could someone help me to solve this problem without using L'Hospital rule? Any hint would be splendid...
lim (sinx-cosx)/(pi-4x)
x-->pi/4
Thanks in advance!