Ordinary Differential Equations

In summary, to solve the given initial value problem, the general solution can be obtained by placing a jump condition on y(t) and integrating the differential equation from t<\tau to t>\tau, with the limit as \varepsilon\rightarrow 0. This will result in the discontinuity of y(t) at t=\tau being equal to 1.
  • #1
sassie
35
0

Homework Statement



Give the general solution to the IVP

L[y]=y'+(sint)y=[tex]\delta[/tex](t-[tex]\tau[/tex])
y(0)=0

For all t>0 by placing a jump condition on y(t) and solving the differential equation for t<[tex]\tau[/tex] and t>[tex]\tau[/tex]

Homework Equations


The Attempt at a Solution



I'm plenty sure I can get the general solution to the problem, but I do not at all know how to get the "jump condition" as it wasn't explained in lectures or in the textbook. Your help is very much appreciated.
 
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  • #2
Integrate the differential equation from [itex]\tau-\varepsilon[/itex] to [itex]\tau+\varepsilon[/itex] and take the limit as [itex]\varepsilon\rightarrow 0[/itex]. That will give you a result that tells you how big the discontinuity in y(t) is at [itex]t=\tau[/itex].
 
  • #3
vela said:
Integrate the differential equation from [itex]\tau-\varepsilon[/itex] to [itex]\tau+\varepsilon[/itex] and take the limit as [itex]\varepsilon\rightarrow 0[/itex]. That will give you a result that tells you how big the discontinuity in y(t) is at [itex]t=\tau[/itex].

So what would we get when we integrate [tex]\delta[/tex](t-[tex]\tau[/tex])? would it be 1?
 
  • #4
Yes, because the interval of integration includes the point [itex]t=\tau[/itex].
 

1. What are Ordinary Differential Equations (ODEs)?

Ordinary Differential Equations (ODEs) are mathematical equations that describe the relationship between a dependent variable and one or more independent variables, in terms of their rates of change. They are used to model many physical, biological, and social phenomena.

2. What is the difference between an ODE and a Partial Differential Equation (PDE)?

The main difference between an ODE and a PDE is the number of independent variables involved. ODEs involve one independent variable, while PDEs involve more than one independent variable. Additionally, in ODEs, the dependent variable and its derivatives are taken with respect to the same independent variable, while in PDEs, the derivatives can be taken with respect to different independent variables.

3. How are ODEs classified?

ODEs are classified based on the order and linearity of the equation. The order of an ODE is the highest derivative present in the equation, while the linearity refers to whether the dependent variable and its derivatives appear in a linear or non-linear form. ODEs can be first-order or higher-order, and can be linear or non-linear.

4. What are some applications of ODEs?

ODEs have a wide range of applications in various fields such as physics, engineering, chemistry, biology, economics, and more. They are used to model the motion of objects, chemical reactions, population growth, electrical circuits, and many other phenomena.

5. What are some methods for solving ODEs?

There are various methods for solving ODEs, including analytical methods such as separation of variables, integrating factors, and series solutions, as well as numerical methods such as Euler's method, Runge-Kutta methods, and finite difference methods. The choice of method depends on the type and complexity of the ODE and the desired level of accuracy.

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