What Frequency Range Keeps the Spring Safe in Driven Oscillations?

Anyway, I'm not going to continue with this. I've given you more than enough leading questions to get started. It's up to you to write the sum of the forces acting on the mass.
  • #36
I'm going to jump out here, two people helping in a thread isn't constructive.

Let me know if you need me to jump back in.
 
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  • #37
Benzoate said:
So I wouldn't write out use Euler term because of the extra constant term?

x= -p^2Ae^ipt -B^2e^-ipt

x'= ipAe^ipt -ipBe^-ipt + 0

x''=-p^2Ae^ipt -B^2e^-ipt+0


x''-1000x= 36eipt -10 , but F(t)=36 cos(t), so trig terms will not completely go away .

You're missing a 1/m and cos(pt)≠e^ipt:

x''-1000x= (36/m)cos(pt) -10=18cos(pt)-10

=>-p^2Ae^ipt -Bp^2e^-ipt-1000(Ae^ipt -B^2e^-ipt)=18cos(pt)-10

But what is cos(pt) in terms of complex exponentials?
 
  • #38
gabbagabbahey said:
You're missing a 1/m and cos(pt)≠e^ipt:

x''-1000x= (36/m)cos(pt) -10=18cos(pt)-10

=>-p^2Ae^ipt -Bp^2e^-ipt-1000(Ae^ipt -B^2e^-ipt)=18cos(pt)-10

But what is cos(pt) in terms of complex exponentials?

Euler Formula:

ei[tex]\theta[/tex]= cos([tex]\theta[/tex])+sin([tex]\theta[/tex])
therefore

18*eipt-10= 18*(cos(pt) + sin (pt))-10
 
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  • #39
But you don't have 18 e^ipt! You have 18 cos(pt).

What is cos(pt) in term of complex exponentials?

Hint: look under the section "Relationship to Trignometry" here
 
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  • #40
gabbagabbahey said:
But you don't have 18 e^ipt! You have 18 cos(pt).

What is cos(pt) in term of complex exponentials?

Hint: look under the section "Relationship to Trignometry" here


sorry if you are becoming frustrated. I have a copy of Gregory Douglass's Classical mechanics books and there is an example like this in that book on p. 10 cos(t) and they say the comple counter part is 10e^it

18 cos(pt)= 18e^ipt - 10(e^0)
 
  • #41
cos(pt)≠e^ipt

Euler's formula gives cos(pt)=Real[e^ipt]=(e^ipt+e^-ipt)/2 (Real[z] is the real part of the complex number z)

so, 18cos(pt)-10=9e^ipt+9e^-ipt-10

=>-p^2Ae^ipt -Bp^2e^-ipt+1000(Ae^ipt +Be^-ipt+C)=9e^ipt+9e^-ipt-10

Compare the coefficients in front of each of the e^ipt,e^-ipt, and constant terms...what must A,B and C be (in terms of p)?
 
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  • #42
gabbagabbahey said:
cos(pt)≠e^ipt

Euler's formula gives cos(pt)=Real[e^ipt]=(e^ipt+e^-ipt)/2 (Real[z] is the real part of the complex number z)

so, 18cos(pt)-10=9e^ipt+9e^-ipt-10

=>-p^2Ae^ipt -Bp^2e^-ipt-1000(Ae^ipt -B^2e^-ipt+C)=9e^ipt+9e^-ipt-10

Compare the coefficients in front of each of the e^ipt,e^-ipt, and constant terms...what must A,B and C be (in terms of p)?

A(p^2-1000)=9 ==> A=9/(p^2-1000)
B(1000-p^2)=9 ==>B=9/(1000-p^2)
C=-10/1000?
 
  • #43
Close, there were some typos in my last equation; you should get A=9/(1000-p^2), your B and C are correct though.

Now, since A and B are equal you have: x(t)=A(e^ipt+e^-ipt)+C=2Acos(pt)+C

Now, if the maximum extension of the spring is 4cm, what must the Value of A be?
 
  • #44
gabbagabbahey said:
Close, there were some typos in my last equation; you should get A=9/(1000-p^2), your B and C are correct though.

Now, since A and B are equal you have: x(t)=A(e^ipt+e^-ipt)+C=2Acos(pt)+C

Now, if the maximum extension of the spring is 4cm, what must the Value of A be?
4=9/(1000-p^2)*cos(pt)-1/100 am I trying to find p?
 
  • #45
Yes, since x(t)=Acos(pt)+C, it should be clear that the angular frequency of oscillation is p. So you want to find p.

You need to be careful of your units though; 4cm =0.04m so you should have:

0.04=9/(1000-p^2)*cos(pt)-1/100

since the rest of the quantities in the equation are in meters.
 
  • #46
gabbagabbahey said:
Yes, since x(t)=Acos(pt)+C, it should be clear that the angular frequency of oscillation is p. So you want to find p.

You need to be careful of your units though; 4cm =0.04m so you should have:

0.04=9/(1000-p^2)*cos(pt)-1/100

since the rest of the quantities in the equation are in meters.

won't there be two solutions to p? The p's I finding for the xD are entirely different from the p's in the complementary function
 
  • #47
Sorry to bumped this thread again, even though its been two days since its been active.
for my final solution I get c=36/(1000-p^2) and c=.04==> p1=10 and p2=-10; I'm not sure what my text means when it says 'spring is safe if p=<20 rad/s and p>=40. rad/s
 

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