Forces Free Body Diagram & Finding μ

In summary, the homework statement mentions that Ff is a known quantity, and that N and Ry are found using the torque equation.
  • #1
jumbogala
423
4

Homework Statement


See the diagram here: http://i47.photobucket.com/albums/f173/xallip/bar2-1.jpg [Broken]

Known quantities: L, Ff.

a) Find the x and y components of A and B.
b) μ is a known quantity; give an expression for A in this case.

Homework Equations


The Attempt at a Solution


a) Rx = Ff
N + Ry - mg = 0
net torque about the blue point must also be zero.

I'm unsure how to calculate the torque, since the entire length of the plank isn't spanned by the step and floor. Does gravity still act at the center of mass, 0.5L? If so then net torque:
0 = 0.9LR - mg0.5Lcosθ

Then I can solve for R: R = (mg0.5Lcosθ)/0.9L = (5/9)mgcosθ

And knowing R and Rx I can get Ry (pythagoras' thm), and from Ry I can find N. Is that correct?

b) This is what's really confusing me! I thought Ff = μN so N = Ff/μ, but I don't think it can be that simple.
 
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  • #2
Is the contact between the corner of the step and the plank frictionless? What does the problem say about that?
 
  • #3
It doesn't say that directly. It just shows Ff in the diagram acting on the blue spot (the floor).

So it doesn't explicitly say it's not frictionless, but I assumed it was. I'm not sure if that's okay, but if it's not I can't assume A is perpendicular to the bar. And if A isn't perpendicular to the bar my torque equation gets messed up...

and it also doesn't show a 90 angle symbol between A and the bar. =S
 
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  • #4
jumbogala said:
It doesn't say that directly. It says "the friction force that stops the bar from sliding has magnitude Ff", and then it shows Ff in the diagram acting on the blue spot (the floor).

So it doesn't explicitly say it's not frictionless, but I assumed it was. I'm not sure if that's okay, but if it's not I can't assume R is perpendicular to the bar. And if R isn't perpendicular to the bar my torque equation gets messed up...

OK. I think you can safely assume that the contact is frictionless - I was just checking. For part (b), yes you can write N = Ff/µ and it's that simple. Usually with this sort of problem you are given µ and you are asked to find the angle at which slipping is just about to start or you are given the critical angle and are asked to find µ. Here you are given both it seems, so it is that simple as long as what you have down as "known quantities" for part (a) do not change in part (b).
 
  • #5
No, the only new known quantity seems to be µ. I guess you could also write B = Rx/µ, but that would probably be pointless.

And it is true that the center of mass is still at 0.5L, and gravity acts there, no matter where the bar is balanced?
 
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  • #6
jumbogala said:
And it is true that the center of mass is still at 0.5L, and gravity acts there, no matter where the bar is balanced?

Yup.
 
  • #7
Okay, thank you so much!
 

1. What is a free body diagram?

A free body diagram is a visual representation of all the forces acting on an object. It is used to analyze the motion of an object and determine the net force acting on it.

2. How do you draw a free body diagram?

To draw a free body diagram, you must first identify all the forces acting on the object. Then, draw a dot to represent the object and draw arrows to represent each force, with the length of the arrow representing the magnitude of the force and the direction of the arrow indicating the direction of the force.

3. What is the difference between static and kinetic friction?

Static friction is the force that prevents an object from moving when a force is applied to it, while kinetic friction is the force that acts on an object when it is already in motion. Static friction is typically greater than kinetic friction.

4. How do you find the coefficient of friction (μ)?

To find the coefficient of friction, you must first measure the force required to move an object at a constant speed. Then, divide this force by the weight of the object. The resulting value is the coefficient of friction.

5. What factors affect the coefficient of friction?

The coefficient of friction can be affected by several factors including the roughness of the surfaces in contact, the weight of the object, and the type of material the object is moving on. It can also be affected by the presence of lubricants or the temperature of the surfaces.

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