What is the Joule-Thomson Coefficient?

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In summary: I have seen a few that skip it, but they are rare.) This is just a summary of the basic principles involved.
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When a real gas, as differentiated from an ideal gas, expands at constant enthalpy (i.e., no heat is transferred to or from the gas, and no external work is extracted), the gas will be either cooled or heated by the expansion. That change in gas temperature with the change in pressure is called the Joule-Thomson coefficient and is denoted by µ, defined as:

µ = (dT/dP) at constant enthalpy

The value of u depends on the specific gas, as well as the temperature and pressure of the gas before expansion. For all real gases, µ will equal zero at some point called the "inversion point". If the gas temperature is below its inversion point temperature, µ is positive ... and if the gas temperature is above its inversion point temperature, µ is negative. Also, dP is always negative when a gas expands. Thus:

If the gas temperature is below its inversion temperature:
-- µ is positive and dP is always negative​
-- hence, the gas cools since dT must be negative​

If the gas temperature is above its inversion temperature:
-- µ is negative and dP is always negative​
-- hence, the gas heats since dT must be positive​

"Perry's Chemical Engineers' Handbook" provides tabulations of µ versus temperature and pressure for a number of gases, as do many other reference books. For most gases at atmospheric pressure, the inversion temperature is fairly high (above room temperature), and so most gases at those temperature and pressure conditions are cooled by isenthalpic expansion.

Helium and hydrogen are two gases whose Joule-Thomson inversion temperatures at atmospheric pressure are very low (e.g., about −222 °C for helium). Thus, helium and hydrogen will warm when expanded at constant enthalpy at atmospheric pressure and typical room temperatures.

It should be noted that µ is always equal to zero for ideal gases (i.e., they will neither heat nor cool upon being expanded at constant enthalpy).

By contrast, when external work is extracted during the expansion of a gas (as when a high-pressure gas is expanded through a turboexpander), the expansion is isentropic (i.e., occurs at constant entropy) rather than isenthalpic as in a Joule-Thomson expansion. For an isentropic gas expansion, the gas temperature always cools and the temperature drop is more than would be achieved by an isenthalpic Joule-Thomson expansion.

Milt Beychok
 
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Thanks for sharing. Very informative.

This was a necro post from 2006. It didn't ask any question, so it got no replies. But it does have 39K views from people who found it via Internet searches. It must be a really hot topic.

In 2019, we have PF Insights for articles in addition to threads for questions. Alas, I can't contact the OP. His email bounces. But I am bumping it in the Materials forum just to bring it to your attention.
 
  • #3
@anorlunda There is a section on Joule-Thomson in practically every thermo book that covers essentially this same material.
 

What is the Joule-Thomson Coefficient?

The Joule-Thomson Coefficient is a thermodynamic property that describes the change in temperature of a gas when it undergoes a throttling process. It is denoted by the symbol μ and is defined as the change in temperature per unit change in pressure at constant enthalpy and entropy.

How is the Joule-Thomson Coefficient calculated?

The Joule-Thomson Coefficient can be calculated using the following formula:
μ = (∂T/∂P)∗(∂P/∂H)S-1
where ∂T/∂P is the slope of the temperature-pressure curve at constant enthalpy, and ∂P/∂HS-1 is the reciprocal of the slope of the pressure-enthalpy curve at constant entropy.

What is the significance of the Joule-Thomson Coefficient?

The Joule-Thomson Coefficient is important in understanding the behavior of gases under different conditions. It helps in predicting the temperature changes that occur when a gas is expanded or compressed, and is used in the design and operation of refrigeration and liquefaction systems.

How does the Joule-Thomson Coefficient differ from the coefficient of thermal expansion?

The Joule-Thomson Coefficient and the coefficient of thermal expansion are both measures of how temperature changes with pressure. However, the Joule-Thomson Coefficient is specifically used for gases, while the coefficient of thermal expansion is used for liquids and solids. Additionally, the Joule-Thomson Coefficient is defined at constant enthalpy and entropy, while the coefficient of thermal expansion is defined at constant volume or pressure.

Can the Joule-Thomson Coefficient be negative?

Yes, the Joule-Thomson Coefficient can be negative. This indicates that the gas is undergoing an inversion, where the temperature decreases when the pressure is decreased. This is often observed in real gases at low temperatures and high pressures.

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