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Joza
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A particle with mass m is fired with initial velocity v at an angle theta with the horizontal. At maximum y, it explodes into 2 paticles of equal mass m/2. One of these has zero initial velocity.
I want to find the energy released in the explosion.
My equation is:
mgy + (1/2)mv^2 = E + (m/2)gy + (1/2)(m/2)(2v)^2 + (m/2)gy
max y distance is ((vsintheta)^2)/g
Thru conservation of momentum, one particle after the explosion has 2 times the original velocity.
Thru cancelling out, I got: (1/2)m(vcostheta)^2 - (1/4)m(2vcostheta)^2
Is this correct? I think my reasoning is correct:
Potential and kinetic energy of particle before explosion = potential energy of 1 particle, + potential and kinetic of the other, + energy released
Sorry if I left anything out. I need this one tho
I want to find the energy released in the explosion.
My equation is:
mgy + (1/2)mv^2 = E + (m/2)gy + (1/2)(m/2)(2v)^2 + (m/2)gy
max y distance is ((vsintheta)^2)/g
Thru conservation of momentum, one particle after the explosion has 2 times the original velocity.
Thru cancelling out, I got: (1/2)m(vcostheta)^2 - (1/4)m(2vcostheta)^2
Is this correct? I think my reasoning is correct:
Potential and kinetic energy of particle before explosion = potential energy of 1 particle, + potential and kinetic of the other, + energy released
Sorry if I left anything out. I need this one tho
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