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[SOLVED] Beam Deflection in a Television Tube
Each of the electrons in the beam of a television tube has a kinetic energy of 10.8 keV. The tube is oriented so that the electrons move horizontally from geomagnetic south to geomagnetic north. The vertical component of Earth's magnetic field points down and has a magnitude of 55.0 µT.
How far will the beam deflect in moving 36.0 cm through the television tube?
F=Bqv
F=ma
K=.5mv^2
d=vi*t + .5at^2 ?
I've already completed the first two parts of the problem:
(a) In what direction will the beam deflect? East
(b) What is the acceleration of a single electron due to the magnetic field? 5.949657e14 m/s^2
I'm honestly not sure how to calculate the deflection...do I use kinematic equations? Thanks for any tips you can provide!
Homework Statement
Each of the electrons in the beam of a television tube has a kinetic energy of 10.8 keV. The tube is oriented so that the electrons move horizontally from geomagnetic south to geomagnetic north. The vertical component of Earth's magnetic field points down and has a magnitude of 55.0 µT.
How far will the beam deflect in moving 36.0 cm through the television tube?
Homework Equations
F=Bqv
F=ma
K=.5mv^2
d=vi*t + .5at^2 ?
The Attempt at a Solution
I've already completed the first two parts of the problem:
(a) In what direction will the beam deflect? East
(b) What is the acceleration of a single electron due to the magnetic field? 5.949657e14 m/s^2
I'm honestly not sure how to calculate the deflection...do I use kinematic equations? Thanks for any tips you can provide!