Simple Harmonic Oscillation Frequency in a Traveling Car

[sru]

Homework Statement

A simple pendulum of mass m and lenghth l is suspended in a car traveling with a constant speed v around a circle of radius r.If the pendulum undergoes small oscillations about its equilibrium position, what will be the frequency of the oscillations??

Homework Equations

$$n=1/2\pi (\sqrt{l/g}$$)
$$mv^2/r =mg$$

The Attempt at a Solution

 

[merryjman]

No attempt at a solution = no advice

 

[baba89]

The frequency of a simple harmonic oscillator is determined by the mass, length, and gravitational acceleration. In this scenario, the only variable that changes is the acceleration due to the car's motion in a circular path. Therefore, the frequency of the pendulum's oscillations will not change and will remain the same as if it were stationary. This is because the gravitational acceleration experienced by the pendulum is still constant, regardless of the car's motion. The equation for the frequency of a simple harmonic oscillator, n = 1/2π√(l/g), does not include any variables related to the car's motion. Therefore, the frequency of the oscillations will remain the same as if the pendulum were stationary.