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ScullyX51
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Homework Statement
A rope hangs from a tree branch, and a bunch of bananas of mass M are tied halfway up the rope. A monkey of mass m hangs on to the end of the rope. Assume the monkey, bananas, and rope are not moving. Neglect the mass of the rope.
1)Draw a FBD of all the forces acting in the monkey. use this to find the tension of the rope just about the monkey.
2) Now think of the monkey and the bananas as a system. Draw a FBD of all the forces acting on this combined system of bananas and monkey, and find the tension in the rope above the bananas.
3)Draw a FBD of the forces acting on the bunch of bananas, and find the tension in the rope above the bananas. How does this tension relate to the answer in part (b)
Homework Equations
f=ma
The Attempt at a Solution
I am getting very confused on this problem because all of my FBD's are coming out the same!
for the monkey: I have mg pointing down in the negative j direction, and "t1" pointing up in the positve j direction. I then calculate t1=mg
for the monkey and the banana as one system: i have "t2" pointing up in the positive j direction and m(total)g pointing down in the negative j direction.
I the calculate t2=m(total)g
...and I have the same thing for the fbd of the bananas.
If anyone can clarify this problem for me if would be great! I don't understand how these tensions differ. I know the masses are different, but those are being multiplied by zero anyway since there is no acceleration.