Solving 910nm-382nm=528nm: Is It Feasible?

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In summary, the conversation discusses the feasibility of combining two laser beams with wavelengths of 910 nm and 382 nm to produce a light at 658 nm. This can be achieved by using a nonlinear crystal and optics, specifically a mirror that reflects one wavelength and transmits the other. However, there must also be a nonlinear crystal that works at these wavelengths, which is uncertain.
  • #1
davesplays
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What would prevent this from being feasible 910nm-382nm-=528nm?
 
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Other wavelengths are produced by taking the sum or difference of the frequencies, or of 1/λ.

So using 910 nm and 382 nm:

1/382 - 1/910 = 0.001519
and
1/0.001519 = 658

So this would produce light at 658 nm. However, there must also be a nonlinear crystal that would work at these wavelengths, and I am not sure if that is the case.
 
  • #3


how would you combine two beams. Using optics or electronics.

Thanks alot

physall
Redbelly98 said:
Other wavelengths are produced by taking the sum or difference of the frequencies, or of 1/λ.

So using 910 nm and 382 nm:

1/382 - 1/910 = 0.001519
and
1/0.001519 = 658

So this would produce light at 658 nm. However, there must also be a nonlinear crystal that would work at these wavelengths, and I am not sure if that is the case.
 
  • #4
Using optics, specifically a "mirror" that reflects one wavelength and transmits the other. For an example, see the final figure at the very bottom of the page here:

http://www.aero.org/publications/crosslink/spring2010/irnd.html

http://www.aero.org/publications/crosslink/spring2010/images/rnd_06.jpg​

The element just to the left of "DFG" is where the two laser beams are combined; the Tunable Laser beam is reflected, and the Nd:YAG beam is transmitted. The difference frequency beam is created within the DFG crystal.

p.s. Welcome to Physics Forums!
 
Last edited:
  • #5


I can confidently say that solving the equation 910nm-382nm=528nm is indeed feasible. This equation follows the basic principles of mathematics and can be solved using simple algebraic techniques. The solution to this equation would be 910nm-382nm=528nm, which is equal to 528nm.

However, there are certain factors that could prevent this equation from being feasible. One factor could be the accuracy of the measurements. If the values of 910nm and 382nm are not precise, then the solution to the equation may not be accurate. Additionally, if the units of measurement are not consistent (for example, if one value is in nanometers and the other is in meters), then the equation cannot be solved.

Another factor that could prevent the feasibility of this equation is the context in which it is being used. If the equation is attempting to solve a physical or scientific problem, there may be other variables and factors at play that could affect the accuracy of the solution.

In summary, solving the equation 910nm-382nm=528nm is feasible, but it is important to consider the accuracy of measurements and the context in which the equation is being used.
 

1. Can this equation be solved using traditional mathematical methods?

Yes, this equation can be solved using traditional mathematical methods such as algebraic manipulation and substitution.

2. What is the significance of the numbers 910nm, 382nm, and 528nm in this equation?

The numbers represent wavelengths of light in the visible spectrum. 910nm is in the near infrared range, 382nm is in the ultraviolet range, and 528nm is in the green range.

3. How can this equation be applied in real-life scenarios?

This equation can be applied in various fields such as optics, physics, and engineering. It can be used to calculate the difference in wavelengths of light and their corresponding colors.

4. Are there any limitations to solving this equation?

The main limitation is the assumption that the equation is linear and does not take into account factors such as refraction or dispersion of light. Additionally, the equation may not be applicable to non-visible wavelengths or in non-optical scenarios.

5. How can this equation be verified or tested?

This equation can be tested by conducting experiments in a controlled environment, using equipment such as spectrometers to measure the wavelengths of light. The results can then be compared to the calculated solution of the equation.

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